frx Group Title Are the following set of vectors in R^4 linearly independent? $\left\{ (1,0,2,-1),(1,2,-1,0),(1,1,0,-1) \right\}$ I want to get the set of vectors into matrixform but the "set" term confuses me a bit. Is this the right form? $\left[\begin{matrix}1 & 0 &2&-1 \\1 & 2 &-1&0 \\1 & 1&0&-1\end{matrix}\right]=\left[\begin{matrix}0 \\ 0 \\0\end{matrix}\right]$ Or is it the other way around? one year ago one year ago

1. Outkast3r09 Group Title

you need to add a row o zeroes

2. frx Group Title

Add a row of zeroes, what do you mean by that?

3. frx Group Title

|dw:1359278439800:dw|

4. frx Group Title

That's how i ussualy write it, is that what you meant?

5. amoodarya Group Title

a(1,0,2,−1)+b(1,2,−1,0)+c(1,1,0,−1)=(0,0,0,0) they are independent if only a=b=c=0 multiply them and solve the system of equation

6. amoodarya Group Title

a+b+c=0 0a+2b+c=0 2a-b+0c=0 -1a+0b-c=0

7. frx Group Title

$a _{1}\left(\begin{matrix}1 \\0 \\ 2\\-1 \end{matrix}\right)+a _{2}\left(\begin{matrix}1 \\2 \\ -1\\0\end{matrix}\right)+a _{3}\left(\begin{matrix}1 \\1 \\ 0\\-1\end{matrix}\right)=\left(\begin{matrix}0 \\0 \\ 0\\0\end{matrix}\right)$ $\left[\begin{matrix}1 & 1 & 1 \\0 & 2 & 1 \\ 2 & -1 & 0 \\-1 & 0 & -1 \end{matrix}\right]=\left(\begin{matrix}0 \\ 0 \\ 0 \\0\end{matrix}\right)$ $\left[\begin{matrix}1 & 0 &0 \\0& 1 & 0 \\ 0&0&1 \\ 0&0&0\end{matrix}\right]=\left[\begin{matrix}0 \\ 0 \\0\\0\end{matrix}\right]$

8. frx Group Title

@amoodarya How should i interpret the reduced matrix, 000=0 but also 001=0 ?

9. frx Group Title

So it can't really be a_3=t it must be a_3=0 and a_1=a_2=a_3=0 and the vectors are linearly independent, am I correct?

10. amoodarya Group Title

do you "rank of matrix" ?

11. frx Group Title

Don't really know what rank of matrix is, will have to look it up.

12. frx Group Title

@amoodarya So the number of linearly independent vectors in the basis is three, so the rank should be three too, but what does this say about the dependent/independent case?