DeadShot
  • DeadShot
Determine the zeros of f(x) = x4 - x3 + 7x2 - 9x - 18.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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shubhamsrg
  • shubhamsrg
-1 fits in.
shubhamsrg
  • shubhamsrg
Got it, break 7 as 9-2 /
DeadShot
  • DeadShot
so \[\pm 1\] is the answer?

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More answers

shubhamsrg
  • shubhamsrg
nopes.
shubhamsrg
  • shubhamsrg
What do get after writing 7 as 9-2 ?
DeadShot
  • DeadShot
\[x^4 - x^3 + 9 - 2x^2 - 9x -18\] ?
shubhamsrg
  • shubhamsrg
x^4 - x^3 + 9x^2 -2x^2 - 9x - 18.=0 =>(x^4 + 9x^2) - (x^3 -9x) -(2x^2 -18) =0 You see what should be the next step ?
DeadShot
  • DeadShot
yeah, factor each binomial, right?
shubhamsrg
  • shubhamsrg
yep.
DeadShot
  • DeadShot
(x^2 + 1) (x^2 + 9) for the first one?
shubhamsrg
  • shubhamsrg
try again.
DeadShot
  • DeadShot
I'm confused
amoodarya
  • amoodarya
x1 = 2 x2 = -1 x3 = 0 + 3i x4 = 0 - 3i
DeadShot
  • DeadShot
So, substitute (0 - 3i) and -1 for x^2, making it ((0 - 3i) + 9(-1))?
DeadShot
  • DeadShot
so, then it would become (-3i - 9)
amoodarya
  • amoodarya
hint : divide f(x) to x^2+9 you would find your answer!
DeadShot
  • DeadShot
So, divide x^4 - x^3 + 7x^2 - 9x - 18 by x^2 + 9 ?
DeadShot
  • DeadShot
so it would be x^2 - x + 7 - x - 2 ?
DeadShot
  • DeadShot
combine like terms, and it would be x^2 - 2x + 5 , right?
anonymous
  • anonymous
Hmm.. Looks like you have 2 real zeros and 2 imaginary.
anonymous
  • anonymous
Do you still need help?
DeadShot
  • DeadShot
yes, I don't know what to do next
DeadShot
  • DeadShot
I got it! Thanks!

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