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|dw:1359278725894:dw|

Find the volume of the water when the cylinder is vertically upwards.

I have tried all. Couldn't crack it.

Just do it.

I will tell you what to do next. I might have got it just by looking at the question.

V = 250pi

So, what next ?

All you need to know: http://mathworld.wolfram.com/CylindricalSegment.html

Do you know how to calculate the volume of apartial cylinder?

Nopes I don't, am referring to the link @frx gave .

|dw:1359279395322:dw|
\[\Large{A=\int_{-5}^h 2\sqrt{5^2-y^2}} \;\mathrm dy\]

it's \[\Large A=\int_{-5}^{5+h}2\sqrt{25-y^2}\;\mathrm dy\]|dw:1359279823727:dw|

@Azteck how do I find "x" ?

that's \(-5+h\) for the upper limit.

I am unable to follow, @sirm3d

i'm sorry. i assumed you know integral calculus.

I do know integral calculus .

Wait, am getting it, 2 mins.

it's the area under the curve.

How do you get 5^2 - y^2 ?

oh wait,

So you're finding the length of an element at a distance y from origin.

|dw:1359280450587:dw|

yes.

Oh wait, RHS will be 0 ./

Seems fine
thanks a lot @sirm3d

Isnt it simply 5 cm as volume of water =1/2 volume of cylinder

|dw:1359287729887:dw|

Indeed!
Re-checked my calculations! It is 5 only!