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ParthKohli
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I seem to be getting \(\frac{3}{8}\), so \(11\), but it is wrong.

ParthKohli
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@shubhamsrg I see that you have solved this problem.

hartnn
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how come denominator = 8 ??

hartnn
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its given that at least one flip results in a head

hartnn
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so, denominator = 8  [TTT] = 7

ParthKohli
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lol, oh yes.

hartnn
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so, 3/7 ...and 10

Jonask
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yeah its correct

ParthKohli
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Of course it is. :)

shubhamsrg
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How did you get to know that I solved it ?

ParthKohli
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@shubhamsrg You were on the list. :)

shubhamsrg
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ohh. :P
I recently joined the site. hmm
Am stuck on one last question at the moment, giving it a try.

ParthKohli
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I got it right :)

hartnn
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which site ?

shubhamsrg
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The cosine rule one ?

shubhamsrg
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brilliant.org

shubhamsrg
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I am posting that question on maths section, unable to do it till now.

ParthKohli
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Cosine rule? There was no such problem.