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ParthKohli

Probability.

  • one year ago
  • one year ago

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  1. ParthKohli
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    I seem to be getting \(\frac{3}{8}\), so \(11\), but it is wrong.

    • one year ago
  2. ParthKohli
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    @shubhamsrg I see that you have solved this problem.

    • one year ago
  3. hartnn
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    how come denominator = 8 ??

    • one year ago
  4. hartnn
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    its given that at least one flip results in a head

    • one year ago
  5. hartnn
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    so, denominator = 8 - [TTT] = 7

    • one year ago
  6. ParthKohli
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    lol, oh yes.

    • one year ago
  7. hartnn
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    so, 3/7 ...and 10

    • one year ago
  8. Jonask
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    yeah its correct

    • one year ago
  9. ParthKohli
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    Of course it is. :-)

    • one year ago
  10. shubhamsrg
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    How did you get to know that I solved it ?

    • one year ago
  11. ParthKohli
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    @shubhamsrg You were on the list. :-)

    • one year ago
  12. shubhamsrg
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    ohh. :P I recently joined the site. hmm Am stuck on one last question at the moment, giving it a try.

    • one year ago
  13. ParthKohli
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    I got it right :-)

    • one year ago
  14. hartnn
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    which site ?

    • one year ago
  15. shubhamsrg
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    The cosine rule one ?

    • one year ago
  16. shubhamsrg
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    brilliant.org

    • one year ago
  17. shubhamsrg
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    I am posting that question on maths section, unable to do it till now.

    • one year ago
  18. ParthKohli
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    Cosine rule? There was no such problem.

    • one year ago
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