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DeadShot Group Title

How would I set this up to solve it? Find the polynomial function with roots 1, 7, and -3 of multiplicity 2.

  • one year ago
  • one year ago

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  1. ParthKohli Group Title
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    All the roots of multiplicity \(2\)?

    • one year ago
  2. ParthKohli Group Title
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    And here's your example: If you want a polynomial with root \(2\) of multiplicity \(3\),\[(x - 2)^3\]

    • one year ago
  3. DeadShot Group Title
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    so, root -3 of multiplicity 2 would be \[(x - (-3))^2\] right?

    • one year ago
  4. ParthKohli Group Title
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    That is correct :-)

    • one year ago
  5. ParthKohli Group Title
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    So is it only \(-3\) with multiplicity \(2\)?

    • one year ago
  6. DeadShot Group Title
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    I have no idea, the question on my homework says "Find the polynomial function with roots 1, 7, and -3 of multiplicity 2.", the teacher didn't say anything else about it.

    • one year ago
  7. DeadShot Group Title
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    so, \[(x-1) (x-7) (x-(-3))^2\] is the correct way to set it up?

    • one year ago
  8. ParthKohli Group Title
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    Yes, that's correct! But if we have all those with multiplicity \(2\),\[(x - 1)^2(x - 7)^2(x + 3)^2\]

    • one year ago
  9. DeadShot Group Title
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    ok, so I'll do all of them with multiplicity of two. \[(x-1)^2 (x-7)^2 (x-(-3))^2\] and then solve it.

    • one year ago
  10. ParthKohli Group Title
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    I dunno, it's your choice. It can be either.

    • one year ago
  11. DeadShot Group Title
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    So, it becomes \[(x^2 + 1) (x^2 + 49) (x^2 + 9)\] right?

    • one year ago
  12. ParthKohli Group Title
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    I think it's just \(-3\) with multiplicity of \(2\).

    • one year ago
  13. ParthKohli Group Title
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    They don't usually give such hard problems.

    • one year ago
  14. DeadShot Group Title
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    oh, so then it's \[(x-1) (x-7) (x^2 + 9)\] right?

    • one year ago
  15. ParthKohli Group Title
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    Hey wait, don't we have the same pics?

    • one year ago
  16. ash2326 Group Title
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    It should be \[(x-1) (x-7) (x + 3)^2\]

    • one year ago
  17. ash2326 Group Title
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    \[(x+3)^2\ne x^2+9\] \[(x+3)^2=x^2+2\times 3\times x+3^2\]

    • one year ago
  18. ParthKohli Group Title
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    Why is OpenStudy so slow right now?

    • one year ago
  19. DeadShot Group Title
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    so, then it's \[(x-1) (x-7) (x^2 + 6x + 9)\] ?

    • one year ago
  20. hartnn Group Title
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    thats correct, but i think you need to multiply them out for final answer, and bring it in the form, ax^4+bx^3+cx^2+dx+e

    • one year ago
  21. ParthKohli Group Title
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    Yes.

    • one year ago
  22. DeadShot Group Title
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    so then the answer is \[(x^4 + 6x^3 - x^3 - 7x^3- x^2 - 7x^2 -6x - 42x - 9 - 63) \] simplified, it is \[(x^4 - 2x^3 - 8x^2 - 48x - 72)\] right?

    • one year ago
  23. ParthKohli Group Title
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    Yup

    • one year ago
  24. DeadShot Group Title
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    ok, thanks!

    • one year ago
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