anonymous
  • anonymous
Two forces with magnitudes of 200 and 100 pounds act on an object at angles of 60° and 170° respectively. Find the direction and magnitude of these forces. Round to two decimal places in all intermediate steps and in your final answer. show work
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
write something down if YOU want a medal
anonymous
  • anonymous
i just need help on the problem please!
anonymous
  • anonymous
plus I am sorry but I do not know the answer

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
calculate the vertical and horizontal components of each force, and then all the vertical forces together, then add horizontal forces together... after that u can combine the vertical and horizontal vector using pythagaros theorem to get the resulting force
anonymous
  • anonymous
im not sure how to do all that .. im horrible in math and im just trying to pass so i can be done:(
anonymous
  • anonymous
I know i have to resolve each vector into horizontal and vertical components using sin and cos but im not sure how to actually begin
geerky42
  • geerky42
Always try to sketch. It may help you.|dw:1359302063400:dw|
geerky42
  • geerky42
Just do what @Tushara told you to do.
anonymous
  • anonymous
i just dont know where or how to really do it :/
mathstudent55
  • mathstudent55
|dw:1359302350812:dw|
geerky42
  • geerky42
|dw:1359302341604:dw|\[\Large \sin \theta = \dfrac{y}{r} \Rightarrow r \sin \theta = y\]\[\Large \cos \theta = \dfrac{x}{r} \Rightarrow r \cos \theta = x\]
anonymous
  • anonymous
but how would i put this all into writing to show my work? like in step form?
mathstudent55
  • mathstudent55
|dw:1359302475063:dw|
anonymous
  • anonymous
i began with this.. is this a good start; f1x= 200cos(60) f1x= 100 cos (170) rx= 200 cos(60) + 100 cos(170)
mathstudent55
  • mathstudent55
F1 = 200, F2 = 100 F1x = F1 cos 60 F1y = F1 sin 60 F2x = f2 cos 170 F2x =F2 sin 170 Rx = F1x + F2x Ry = F1y + F2y R(theta) = tan^1(Ry/Rx)
mathstudent55
  • mathstudent55
On the second line, you mean f2x, but that's good.
anonymous
  • anonymous
but now where do i go ?
mathstudent55
  • mathstudent55
Now do the same for the force components in the y direction.
anonymous
  • anonymous
whhat do u mean?
mathstudent55
  • mathstudent55
Do this: f1x= 200cos(60) f2x= 100 cos (170) rx= 200 cos(60) + 100 cos(170) For F1y, F2y, and Ry
mathstudent55
  • mathstudent55
F1y = F1 sin 170 F2y = ... Ry = F1y + F2y = ...
anonymous
  • anonymous
f1y = 100 sin (170) f2y = 200 sin ( ) ?? hmm
mathstudent55
  • mathstudent55
F1 = 200, F2 = 100. You switched them.
anonymous
  • anonymous
f1 = 200 sin (170) f2 = 100 sin (60) ??
anonymous
  • anonymous
okay the it would be ..
mathstudent55
  • mathstudent55
You got the x-components above and you did it correctly. Now you need the y-components. f1y = 200 sin (60) f2y = 100 sin (170) Ry = f1y + f2y = 200 sin 60 + 100 sin 170
anonymous
  • anonymous
ok i got the 70 and 170 mixed around
mathstudent55
  • mathstudent55
There is no 70.
anonymous
  • anonymous
i mean 60*
anonymous
  • anonymous
sorry!
mathstudent55
  • mathstudent55
Remember the first force, F1, is 200 lb at 60 deg The x component is F1x = 200 cos 60 The y component is F1y = 200 sin 60 The second force, F2, is 100 lb at 170 deg The x component is F2x = 100 cos 170 The y component is F2y = 100 sin 170 The resultant's x-component is Rx = F1x + F2x = 200 cos 60 + 100 cos 170 The resultant's y-component is Ry = F1y + F2y = 200 sin 60 + 100 sin 170
mathstudent55
  • mathstudent55
Now you need to do the actual calculations with a calculator of what Rx and Ry are, and round off to 2 decimal places.
anonymous
  • anonymous
so all i have to do is put the equation in the calculator for rx and ry and thatll give me the answers?
anonymous
  • anonymous
i need to complete the problem?
mathstudent55
  • mathstudent55
For now, yes. That will give you the x- and y-components of the resultant.
anonymous
  • anonymous
okay .. and thats all i do then right
anonymous
  • anonymous
but i have to find the direction and magnitude?
anonymous
  • anonymous
??
mathstudent55
  • mathstudent55
Once you have the x- and y-components of the resultant, you need two more steps. 1. You need to find the magnitude of the resultant. 2. You need to find the direction of the resultant.
anonymous
  • anonymous
how do i do that?
mathstudent55
  • mathstudent55
For the magnitude of the resultant, you use the Pythagoras theorem. For the direction of the resultant, you use the inverse tangent to get the angle. See figure below: |dw:1359304507660:dw|
mathstudent55
  • mathstudent55
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.