A community for students.
Here's the question you clicked on:
 0 viewing
DLS
 2 years ago
What on earth is the oxidation number of N in N2H4?
DLS
 2 years ago
What on earth is the oxidation number of N in N2H4?

This Question is Closed

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0Each bond with H gives 2 electrons to the N dw:1359301726739:dw

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1359301793906:dw The N's are equal so 1 electron to each

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0Now each N has 7 electrons, can you figure out the oxidation number?

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0It has extra electrons, so it's negative, so yes, 2 :)

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0answer=+2 thats what confuses me

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0OK i was a bit confused, here this explanation is better : http://answers.yahoo.com/question/index?qid=20071023171027AA07wRO

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0i didnt get t hat explanation,sry

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0Aere you sure it's +2? I'm pretty sure it's 2...

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.0Well the way the guy on Yahoo Answers is solving it is like this: The overall state of the Hydrogens is 4, since each hydrogen gives 1 when bonded to a nonmetal. The overall state of the entire molecule is 0 (no charge). So the overall state of the N's must balance out with the overall state of the H's to give 0. So the overall state of the N's must be +4, since 4+4 = 0. Since there are 2 N's, each N is +2

Naerro
 2 years ago
Best ResponseYou've already chosen the best response.1When you have to determine the oxidation numbers in a molecule, imagine dividing it into ions. The electrons always go to the element with the higher electronegativity. In this case H has electronegativity 2.1 and N was 3.0 so N gets all the electrons. As a result H has an oxidation number +1 (with no electrons left) and N has 2 (with 7 electrons). It seems the answer is mistaken in the book. Btw the guy on Yahoo was switched it around. H was +1 when bonded to a nonmetal and 1 when bonded to metal.

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0http://www.chacha.com/question/whatistheoxidationstateofnitrogeninn2h4

Naerro
 2 years ago
Best ResponseYou've already chosen the best response.1@DLS: About your link: either that's the same Yahoo guy answering or somebody has copied his answer. The wording is pretty much the same. I could link you to a German site where the oxidation number of N is 2 (scroll down to Hydrazin, there's a picture): http://www.guidobauersachs.de/oxi/oxi.htm. They don't explain the determination of the oxidation number there so the language shouldn't be a problem. I'm not trying to convince you with internet links though. They can always be wrong. What matters in this case is the electronegativity principle.

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0It can be a matter of definition, but that should not be. In your compound, oxidation number of N is 2, as far as France is concerned.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.