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BluFootBest ResponseYou've already chosen the best response.0
Each bond with H gives 2 electrons to the N dw:1359301726739:dw
 one year ago

BluFootBest ResponseYou've already chosen the best response.0
dw:1359301793906:dw The N's are equal so 1 electron to each
 one year ago

BluFootBest ResponseYou've already chosen the best response.0
Now each N has 7 electrons, can you figure out the oxidation number?
 one year ago

BluFootBest ResponseYou've already chosen the best response.0
It has extra electrons, so it's negative, so yes, 2 :)
 one year ago

DLSBest ResponseYou've already chosen the best response.0
answer=+2 thats what confuses me
 one year ago

BluFootBest ResponseYou've already chosen the best response.0
OK i was a bit confused, here this explanation is better : http://answers.yahoo.com/question/index?qid=20071023171027AA07wRO
 one year ago

DLSBest ResponseYou've already chosen the best response.0
i didnt get t hat explanation,sry
 one year ago

BluFootBest ResponseYou've already chosen the best response.0
Aere you sure it's +2? I'm pretty sure it's 2...
 one year ago

BluFootBest ResponseYou've already chosen the best response.0
Well the way the guy on Yahoo Answers is solving it is like this: The overall state of the Hydrogens is 4, since each hydrogen gives 1 when bonded to a nonmetal. The overall state of the entire molecule is 0 (no charge). So the overall state of the N's must balance out with the overall state of the H's to give 0. So the overall state of the N's must be +4, since 4+4 = 0. Since there are 2 N's, each N is +2
 one year ago

NaerroBest ResponseYou've already chosen the best response.1
When you have to determine the oxidation numbers in a molecule, imagine dividing it into ions. The electrons always go to the element with the higher electronegativity. In this case H has electronegativity 2.1 and N was 3.0 so N gets all the electrons. As a result H has an oxidation number +1 (with no electrons left) and N has 2 (with 7 electrons). It seems the answer is mistaken in the book. Btw the guy on Yahoo was switched it around. H was +1 when bonded to a nonmetal and 1 when bonded to metal.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
http://www.chacha.com/question/whatistheoxidationstateofnitrogeninn2h4
 one year ago

NaerroBest ResponseYou've already chosen the best response.1
@DLS: About your link: either that's the same Yahoo guy answering or somebody has copied his answer. The wording is pretty much the same. I could link you to a German site where the oxidation number of N is 2 (scroll down to Hydrazin, there's a picture): http://www.guidobauersachs.de/oxi/oxi.htm. They don't explain the determination of the oxidation number there so the language shouldn't be a problem. I'm not trying to convince you with internet links though. They can always be wrong. What matters in this case is the electronegativity principle.
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
It can be a matter of definition, but that should not be. In your compound, oxidation number of N is 2, as far as France is concerned.
 one year ago
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