At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Each bond with H gives 2 electrons to the N |dw:1359301726739:dw|
|dw:1359301793906:dw| The N's are equal so 1 electron to each
Now each N has 7 electrons, can you figure out the oxidation number?
is it +2 or -2?
It has extra electrons, so it's negative, so yes, -2 :)
answer=+2 thats what confuses me
that's odd... hmm
OK i was a bit confused, here this explanation is better : http://answers.yahoo.com/question/index?qid=20071023171027AA07wRO
i didnt get t hat explanation,sry
mind explaining ?? :o
Aere you sure it's +2? I'm pretty sure it's -2...
my book says +2
Well the way the guy on Yahoo Answers is solving it is like this: The overall state of the Hydrogens is -4, since each hydrogen gives -1 when bonded to a non-metal. The overall state of the entire molecule is 0 (no charge). So the overall state of the N's must balance out with the overall state of the H's to give 0. So the overall state of the N's must be +4, since -4+4 = 0. Since there are 2 N's, each N is +2
When you have to determine the oxidation numbers in a molecule, imagine dividing it into ions. The electrons always go to the element with the higher electronegativity. In this case H has electronegativity 2.1 and N was 3.0 so N gets all the electrons. As a result H has an oxidation number +1 (with no electrons left) and N has -2 (with 7 electrons). It seems the answer is mistaken in the book. Btw the guy on Yahoo was switched it around. H was +1 when bonded to a non-metal and -1 when bonded to metal.
@DLS: About your link: either that's the same Yahoo guy answering or somebody has copied his answer. The wording is pretty much the same. I could link you to a German site where the oxidation number of N is -2 (scroll down to Hydrazin, there's a picture): http://www.guidobauersachs.de/oxi/oxi.htm. They don't explain the determination of the oxidation number there so the language shouldn't be a problem. I'm not trying to convince you with internet links though. They can always be wrong. What matters in this case is the electronegativity principle.
It can be a matter of definition, but that should not be. In your compound, oxidation number of N is -2, as far as France is concerned.