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anonymous
 3 years ago
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
anonymous
 3 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = <8, 7>, v = <9, 7>

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You could use the formula:\[\cos \theta=\frac{ \vec u \cdot \vec v}{ \vec u\vec v }\]assuming you are familiar with the dot product of vectors.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here it is on mathematica.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that wouldnt let me open it @Sshmoo

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im just learning it so im still so comfused

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i'll try converting it to a different file, all it is is a graph of the vectors and a dot product. It just looks shinier.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so which of these would the answer be ? 8.3° 1.7° 3.3° 13.3°

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you calculate cos theta, you get: \[\cos \theta=\frac{ 8 \cdot 9 + 7 \cdot 7 }{ \sqrt{8^2+7^2}\sqrt{9^2+7^2} }=\frac{ 72+49 }{\sqrt{113}\sqrt{130} }=\frac{ 121 }{ \sqrt{113} \sqrt{130}}\approx 0.99833\]Now take the inverse cosine (cos^1 on your calculator) to see the answer.
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