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DeadShot

  • 3 years ago

help? Find the polynomial function with roots 11 and 2i.

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  1. dpaInc
    • 3 years ago
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    since complex roots come in conjugate pairs, the polynomial has to also have -2i as one of the roots... so the polynomial having 11, 2i, -2i as roots has to be at least a third degree polynomial

  2. DeadShot
    • 3 years ago
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    so, it would be (x - 11) (x - 2i) (x - (-2i)) ?

  3. DeadShot
    • 3 years ago
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    \[(x^3 -11x^2 -2ix^2 +2ix^2 + 22i -22i -4i^2)\] that's the unsimplified answer, so the simplified one is \[(x^3 - 11x^2 -4i^2)\] right?

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