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anonymous
 3 years ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 2 = 1/3x – 5/3; (–4, 3)
anonymous
 3 years ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point. y + 2 = 1/3x – 5/3; (–4, 3)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y = –3x + 15 y = –3x – 9 y = –4x + 3 y = –1/3x – 11

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Use the rule: if lines are perpendicular then m1*m2=1, where m1 and m2 are the slopes of the lines. The slope of your line is 1/3. With the rule you can work out the other slope.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Once you've got that other slope, you have this equation for tha line: y=m2*x + b. To get b, use the given point: (4,3), so set x=4 and y=3.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you do this calculation, you will see b is wrong...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im honestly so lost on this one.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01/3 * 3 = 1, so m2 = 3. Equation: y=3x+b. Point on line: (4,3). Set x=4, y=3: 3=3*4+b so 3 = 12 + b b = 3 12 = 9. Equation y = 3 x 9 Answer b IS right , I was WRONG! (Sorry...)
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