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 one year ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 2 = 1/3x – 5/3; (–4, 3)
 one year ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point. y + 2 = 1/3x – 5/3; (–4, 3)

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Southerngirl265
 one year ago
Best ResponseYou've already chosen the best response.0y = –3x + 15 y = –3x – 9 y = –4x + 3 y = –1/3x – 11

Southerngirl265
 one year ago
Best ResponseYou've already chosen the best response.0i think it is b

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1Use the rule: if lines are perpendicular then m1*m2=1, where m1 and m2 are the slopes of the lines. The slope of your line is 1/3. With the rule you can work out the other slope.

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1Once you've got that other slope, you have this equation for tha line: y=m2*x + b. To get b, use the given point: (4,3), so set x=4 and y=3.

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.1If you do this calculation, you will see b is wrong...

Southerngirl265
 one year ago
Best ResponseYou've already chosen the best response.0im honestly so lost on this one.

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.11/3 * 3 = 1, so m2 = 3. Equation: y=3x+b. Point on line: (4,3). Set x=4, y=3: 3=3*4+b so 3 = 12 + b b = 3 12 = 9. Equation y = 3 x 9 Answer b IS right , I was WRONG! (Sorry...)
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