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ksaimouli
 2 years ago
find the arc lenght x=(y^3/3)((x^2)+2)^3/2 from x=0 to x=3
ksaimouli
 2 years ago
find the arc lenght x=(y^3/3)((x^2)+2)^3/2 from x=0 to x=3

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ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0\[x=\frac{ y^3 }{ 6 }+\frac{ 1 }{ 2y }\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dx}{ dy }=\frac{ y^2 }{ 2 }\frac{ 1 }{ y^2}\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{2}\sqrt{1+((\frac{ y^2 }{ 2 })\frac{ 1 }{ y^2 })^2} dy\]

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Woops the 2 should still be there on the second term. A 1 came down from the power rule.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1The problem at the very top seems to be different than the one you formatted below it, I'm confused..

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0when i take derivative using quotient rule i got 1/2y^2

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Yes that's the correct derivative. Don't use quotient rule, easier to use power rule.\[\large \left(\frac{1}{2y}\right)'\quad = \quad \left(\frac{1}{2}y^{1}\right)' \quad = \quad \frac{1}{2}y^{2}\]

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Do you have 2 separate problems listed? This is rather confusing....
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