A community for students.
Here's the question you clicked on:
 0 viewing
ksaimouli
 3 years ago
find the arc lenght x=(y^3/3)((x^2)+2)^3/2 from x=0 to x=3
ksaimouli
 3 years ago
find the arc lenght x=(y^3/3)((x^2)+2)^3/2 from x=0 to x=3

This Question is Closed

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0\[x=\frac{ y^3 }{ 6 }+\frac{ 1 }{ 2y }\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dx}{ dy }=\frac{ y^2 }{ 2 }\frac{ 1 }{ y^2}\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{2}\sqrt{1+((\frac{ y^2 }{ 2 })\frac{ 1 }{ y^2 })^2} dy\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Woops the 2 should still be there on the second term. A 1 came down from the power rule.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1The problem at the very top seems to be different than the one you formatted below it, I'm confused..

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0when i take derivative using quotient rule i got 1/2y^2

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Yes that's the correct derivative. Don't use quotient rule, easier to use power rule.\[\large \left(\frac{1}{2y}\right)'\quad = \quad \left(\frac{1}{2}y^{1}\right)' \quad = \quad \frac{1}{2}y^{2}\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Do you have 2 separate problems listed? This is rather confusing....
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.