A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
differentiate:
y= (ae^{x} + b)/(ce^{x} + d)
anonymous
 3 years ago
differentiate: y= (ae^{x} + b)/(ce^{x} + d)

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[y=\frac{ ae ^{x} + b }{ ce ^{x} +d } \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0f(x) = ae^x + b, then f'(x) = ae^x g(x) = ce^x + d, then g'(x) = ce^x You have y = f(x)/g(x) The derivative of this is (f'(x)*g(x)  g'(x)*f(x))/g(x)^2 So ((ae^x)(ce^x + d)  (ce^x)(ae^x + b))/(ce^x)^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hmmm that's what I got but it says the answer is: \[\frac{ (adbc)e ^{x} }{ (ce ^{x}+d)^{2} }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you multiply everything on the top out, you get ace^(2x) + ade^x  ace^(2x)  bce^x ===> ade^x  bce^x ==> (adbc)e^x I also mistyped something in my earlier answer, it should be (ce^x +d)^2 on the bottom. Sorry about that.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.