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 one year ago
would someone please help me find the limit of (e^x + 2cos(3x) as x approaches inifinity? I'm stuck on the math. I came up with 0 as an answer, but I think I'm wrong. Would someone help me break it down step by step to find my error? Thank you.
 one year ago
would someone please help me find the limit of (e^x + 2cos(3x) as x approaches inifinity? I'm stuck on the math. I came up with 0 as an answer, but I think I'm wrong. Would someone help me break it down step by step to find my error? Thank you.

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satellite73
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{x\to \infty} e^{x}=0\] but \(\lim_{x\to \infty}\cos(x)\) does not exist, as cosine is periodic

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1cosine oscillates between 1 and 1 infinitely often

turbomatt75
 one year ago
Best ResponseYou've already chosen the best response.0ok..I see what you are saying...so in this case because the two limits are not equal, then this limit does not exist...is that what you are saying?
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