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turbomatt75
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would someone please help me find the limit of (e^x + 2cos(3x) as x approaches inifinity? I'm stuck on the math. I came up with 0 as an answer, but I think I'm wrong. Would someone help me break it down step by step to find my error? Thank you.
 one year ago
 one year ago
turbomatt75 Group Title
would someone please help me find the limit of (e^x + 2cos(3x) as x approaches inifinity? I'm stuck on the math. I came up with 0 as an answer, but I think I'm wrong. Would someone help me break it down step by step to find my error? Thank you.
 one year ago
 one year ago

This Question is Closed

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[\lim_{x\to \infty} e^{x}=0\] but \(\lim_{x\to \infty}\cos(x)\) does not exist, as cosine is periodic
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
cosine oscillates between 1 and 1 infinitely often
 one year ago

turbomatt75 Group TitleBest ResponseYou've already chosen the best response.0
ok..I see what you are saying...so in this case because the two limits are not equal, then this limit does not exist...is that what you are saying?
 one year ago
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