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## turbomatt75 Group Title would someone please help me find the limit of (e^-x + 2cos(3x) as x approaches inifinity? I'm stuck on the math. I came up with 0 as an answer, but I think I'm wrong. Would someone help me break it down step by step to find my error? Thank you. one year ago one year ago

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1. satellite73 Group Title

$\lim_{x\to \infty} e^{-x}=0$ but $$\lim_{x\to \infty}\cos(x)$$ does not exist, as cosine is periodic

2. satellite73 Group Title

cosine oscillates between -1 and 1 infinitely often

3. turbomatt75 Group Title

ok..I see what you are saying...so in this case because the two limits are not equal, then this limit does not exist...is that what you are saying?