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treydwg

  • one year ago

64s^2+144s=-81 can anyone help on this one. Solving for s

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  1. marsss
    • one year ago
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    64s^2+144s+81=0 (8s+9)^2=0 8s+9=0 8s=-9 s=-9/8

  2. treydwg
    • one year ago
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    hmmm?

  3. treydwg
    • one year ago
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    @marsss Thank you for the setup

  4. godorovg
    • one year ago
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    I think this problem is quadtradic

  5. treydwg
    • one year ago
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    i believe it is too

  6. marsss
    • one year ago
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    @godorovg you're a genius :)

  7. marsss
    • one year ago
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    @treydwg you're too :)

  8. treydwg
    • one year ago
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    thanks lol

  9. treydwg
    • one year ago
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    so the solution set would be

  10. treydwg
    • one year ago
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    I working on it

  11. godorovg
    • one year ago
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    in this problem the first clue is being = 0 usally says Quad needs to be used.

  12. treydwg
    • one year ago
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    What is the easier way of working out qUADRATIC without using the quad formula?

  13. godorovg
    • one year ago
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    64^2 is a peferct square so that always tells that this will invole in a square root to slove

  14. godorovg
    • one year ago
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    you could use a^2+B^2=c^2 as well

  15. treydwg
    • one year ago
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    So I got -1.125, -1.125. Can I write -1.125^2. Or is this considered incorrect?

  16. godorovg
    • one year ago
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    yes you can do that with 1.125^2 if you used the Quad form you would plus ninus which is what the problem is asking for..

  17. treydwg
    • one year ago
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    Ok i just wrote it twice. lets see if it counts it correct?

  18. godorovg
    • one year ago
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    treydwg first thing to know in this problem 64s^2+144s+81=0 all of the numbers are perfect squares. what that means taking the square root will be a number for example you take square root of 81 which is, we can check this by 9^2 and yes it equals 9.

  19. treydwg
    • one year ago
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    ok

  20. treydwg
    • one year ago
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    what about 2v^2+7v+5 and I need tofactor by grouping?

  21. treydwg
    • one year ago
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    I am at (2v^2+5v)(2v+5) and stuck

  22. treydwg
    • one year ago
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    @godorovg can you assist?

  23. godorovg
    • one year ago
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    yes

  24. treydwg
    • one year ago
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    where do I go from here?

  25. godorovg
    • one year ago
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    in this problem we need to use F,.O.I .L

  26. treydwg
    • one year ago
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    ok yes

  27. godorovg
    • one year ago
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    so now take the 2v^2 and times to 2v what is the answer

  28. treydwg
    • one year ago
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    4v^2

  29. godorovg
    • one year ago
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    close try again

  30. godorovg
    • one year ago
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    4v is right your power is wrong

  31. treydwg
    • one year ago
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    where are you getting the 2v^2*2v?

  32. godorovg
    • one year ago
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    because you typed 4v^2 while ago

  33. godorovg
    • one year ago
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    recall the problem here (2v^2+5v)(2v+5)

  34. treydwg
    • one year ago
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    yes that what I have

  35. treydwg
    • one year ago
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    2v(v+5)

  36. treydwg
    • one year ago
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    the (2v+5) is where im stuck

  37. treydwg
    • one year ago
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    what can I factor out of that?

  38. godorovg
    • one year ago
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    now 4v is right because 2v times 2v =4v^2 but that is not what is happening here. You have a power being times by V what is the power of the V? that power of the V is ^1 and when times 2v^2 time 2v = 4v^3

  39. godorovg
    • one year ago
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    so what happened here is we times the 2's to get 4 and v^2 + v^1 =V^3 see that

  40. treydwg
    • one year ago
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    let me look at that hold on

  41. treydwg
    • one year ago
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    ok I see it

  42. treydwg
    • one year ago
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    now how do I fix the last part?

  43. godorovg
    • one year ago
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    if you have a question plz ask me..

  44. godorovg
    • one year ago
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    factoring will not be in use unti we finish F.O.I.L

  45. treydwg
    • one year ago
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    I have (2v+5) how can I faactor this

  46. godorovg
    • one year ago
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    no you can not factor that..

  47. treydwg
    • one year ago
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    ok I see now so this is what I have after foil 4v^3+10v^2+35v

  48. godorovg
    • one year ago
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    now we can factor

  49. treydwg
    • one year ago
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    oooooooooh

  50. treydwg
    • one year ago
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    by grouping?

  51. godorovg
    • one year ago
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    no grouping there are no a like terms here

  52. treydwg
    • one year ago
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    I know but i was going to use 35v and try to make another number to group

  53. godorovg
    • one year ago
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    can not do that srry

  54. treydwg
    • one year ago
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    ok so wehre from here

  55. treydwg
    • one year ago
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    no GCF in common

  56. godorovg
    • one year ago
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    okay let us look at this 4v^3+10v^2+35v what is the same with all the numbers?

  57. treydwg
    • one year ago
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    v

  58. godorovg
    • one year ago
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    yes V so how many V's can be factored?

  59. treydwg
    • one year ago
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    1

  60. treydwg
    • one year ago
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    v(2v^2+10v+35)

  61. godorovg
    • one year ago
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    now look at the numbers what can each number be divided by?

  62. treydwg
    • one year ago
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    v(4v^2+10v+35)

  63. godorovg
    • one year ago
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    that is the answer it can not be factored any further

  64. treydwg
    • one year ago
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    ahhhhhhh! Thats my problem i want to always factor further :/

  65. treydwg
    • one year ago
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    Thank you

  66. godorovg
    • one year ago
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    treydwg here is a help for you, if you have done all the factoring right than find a number that divides in to the first and see if it works for example 2 will go ino 4 =2 2 will also go into 10 five times but here is a question for you will 2 divide even into 35?

  67. godorovg
    • one year ago
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    if the answer is no than you are finished..

  68. treydwg
    • one year ago
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    no it wont and that was my problem

  69. treydwg
    • one year ago
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    thanks

  70. godorovg
    • one year ago
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    welcome anytime

  71. godorovg
    • one year ago
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    before I leave any questions plz ask me

  72. treydwg
    • one year ago
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    thanks

  73. treydwg
    • one year ago
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    working on another

  74. godorovg
    • one year ago
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    If you need help I am here

  75. treydwg
    • one year ago
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    5x-3=14x+6 I got x=-1

  76. godorovg
    • one year ago
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    no

  77. godorovg
    • one year ago
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    5x-3=14x+6 get a like terms together so we x terms let us put the tgether like this 14x-5x=6-3 recall when a + or - crosses the equals sign it changes

  78. treydwg
    • one year ago
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    x=3/9??

  79. godorovg
    • one year ago
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    yes that is right

  80. treydwg
    • one year ago
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    ok i did that one a little wrong thank you

  81. treydwg
    • one year ago
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    now this one is throwing me off cuz the a^2 I have a^2=10-3a I got a^2=5/2

  82. godorovg
    • one year ago
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    no now think about this one? come you do it!!

  83. treydwg
    • one year ago
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    ok

  84. godorovg
    • one year ago
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    first off you can not a^2 = 10 -3a and come out with a^2=5/2 no..

  85. godorovg
    • one year ago
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    hint what happens to the problem when all nunbers are moved like this a^2+3a-10= what is this problem?

  86. treydwg
    • one year ago
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    um

  87. godorovg
    • one year ago
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    what did I say when a problem is set to zero is?

  88. treydwg
    • one year ago
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    nothing is on one side

  89. treydwg
    • one year ago
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    or they are all on one side rather

  90. treydwg
    • one year ago
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    have to factor?

  91. godorovg
    • one year ago
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    recall the problem a^2 = 10 -3a now look at the problem a^2+3a-10=

  92. treydwg
    • one year ago
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    0

  93. treydwg
    • one year ago
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    we have to find something in common

  94. godorovg
    • one year ago
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    so what type of problem is this? not factoring

  95. treydwg
    • one year ago
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    quadratic equation

  96. godorovg
    • one year ago
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    yes

  97. treydwg
    • one year ago
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    so i need to find out what two numbers product is 10 and sum is 3 right?

  98. godorovg
    • one year ago
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    yes but I will let you try this way.

  99. treydwg
    • one year ago
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    k

  100. godorovg
    • one year ago
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    don't forget the a^2

  101. treydwg
    • one year ago
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    a^2-2a+5a-10=0

  102. treydwg
    • one year ago
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    (a+5)(a-2)

  103. godorovg
    • one year ago
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    GREAT JOB!!!

  104. treydwg
    • one year ago
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    awesome thank you again!

  105. treydwg
    • one year ago
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    so the solution set is (a+5)(a-2)?

  106. godorovg
    • one year ago
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    now I want you to check this

  107. treydwg
    • one year ago
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    k how do I check?

  108. godorovg
    • one year ago
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    simply take this (a+5)(a-2) use F.O.I.L and see if you get this back a^2+3a-10=

  109. godorovg
    • one year ago
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    if you do than you are right..

  110. treydwg
    • one year ago
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    alright

  111. godorovg
    • one year ago
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    did you get it?

  112. godorovg
    • one year ago
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    treydwg if you need help let me know..

  113. treydwg
    • one year ago
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    now I got this one wrong? dont know why? r^2+2r-48 I got (r+8)(r-6)

  114. treydwg
    • one year ago
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    sorry working on another one

  115. godorovg
    • one year ago
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    which the - to 8 and try again

  116. treydwg
    • one year ago
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    but 6-8 = -2 and not 2

  117. godorovg
    • one year ago
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    try both -

  118. treydwg
    • one year ago
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    that gives me a +48 and not -48

  119. treydwg
    • one year ago
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    i am pretty sure im right but the computer counted it wrong??

  120. godorovg
    • one year ago
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    treydwg is this a test?

  121. treydwg
    • one year ago
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    yeah but I have three times to take

  122. treydwg
    • one year ago
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    I can not figure this out and i know im right!

  123. treydwg
    • one year ago
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    can you figure out why its wrong?

  124. godorovg
    • one year ago
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    give me a minute

  125. treydwg
    • one year ago
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    I have already taken the test. just reviewing results

  126. godorovg
    • one year ago
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    okay that is better, I can get big trouble for helping on tests..

  127. godorovg
    • one year ago
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    because you have taken it already no worries

  128. treydwg
    • one year ago
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    yes all done and really confused because my answers I beleive are correct. There are many more like that. Have you figured out why im wrong?

  129. godorovg
    • one year ago
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    working on it

  130. treydwg
    • one year ago
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    thank you

  131. godorovg
    • one year ago
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    okay try 24 times and see what happens and work it again

  132. godorovg
    • one year ago
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    2

  133. godorovg
    • one year ago
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    24 times 2?

  134. treydwg
    • one year ago
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    k

  135. godorovg
    • one year ago
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    friends are here

  136. godorovg
    • one year ago
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    brb for me I have company over will back soon

  137. treydwg
    • one year ago
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    thank you

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