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treydwg Group Title

64s^2+144s=-81 can anyone help on this one. Solving for s

  • one year ago
  • one year ago

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  1. marsss Group Title
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    64s^2+144s+81=0 (8s+9)^2=0 8s+9=0 8s=-9 s=-9/8

    • one year ago
  2. treydwg Group Title
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    hmmm?

    • one year ago
  3. treydwg Group Title
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    @marsss Thank you for the setup

    • one year ago
  4. godorovg Group Title
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    I think this problem is quadtradic

    • one year ago
  5. treydwg Group Title
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    i believe it is too

    • one year ago
  6. marsss Group Title
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    @godorovg you're a genius :)

    • one year ago
  7. marsss Group Title
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    @treydwg you're too :)

    • one year ago
  8. treydwg Group Title
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    thanks lol

    • one year ago
  9. treydwg Group Title
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    so the solution set would be

    • one year ago
  10. treydwg Group Title
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    I working on it

    • one year ago
  11. godorovg Group Title
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    in this problem the first clue is being = 0 usally says Quad needs to be used.

    • one year ago
  12. treydwg Group Title
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    What is the easier way of working out qUADRATIC without using the quad formula?

    • one year ago
  13. godorovg Group Title
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    64^2 is a peferct square so that always tells that this will invole in a square root to slove

    • one year ago
  14. godorovg Group Title
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    you could use a^2+B^2=c^2 as well

    • one year ago
  15. treydwg Group Title
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    So I got -1.125, -1.125. Can I write -1.125^2. Or is this considered incorrect?

    • one year ago
  16. godorovg Group Title
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    yes you can do that with 1.125^2 if you used the Quad form you would plus ninus which is what the problem is asking for..

    • one year ago
  17. treydwg Group Title
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    Ok i just wrote it twice. lets see if it counts it correct?

    • one year ago
  18. godorovg Group Title
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    treydwg first thing to know in this problem 64s^2+144s+81=0 all of the numbers are perfect squares. what that means taking the square root will be a number for example you take square root of 81 which is, we can check this by 9^2 and yes it equals 9.

    • one year ago
  19. treydwg Group Title
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    ok

    • one year ago
  20. treydwg Group Title
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    what about 2v^2+7v+5 and I need tofactor by grouping?

    • one year ago
  21. treydwg Group Title
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    I am at (2v^2+5v)(2v+5) and stuck

    • one year ago
  22. treydwg Group Title
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    @godorovg can you assist?

    • one year ago
  23. godorovg Group Title
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    yes

    • one year ago
  24. treydwg Group Title
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    where do I go from here?

    • one year ago
  25. godorovg Group Title
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    in this problem we need to use F,.O.I .L

    • one year ago
  26. treydwg Group Title
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    ok yes

    • one year ago
  27. godorovg Group Title
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    so now take the 2v^2 and times to 2v what is the answer

    • one year ago
  28. treydwg Group Title
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    4v^2

    • one year ago
  29. godorovg Group Title
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    close try again

    • one year ago
  30. godorovg Group Title
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    4v is right your power is wrong

    • one year ago
  31. treydwg Group Title
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    where are you getting the 2v^2*2v?

    • one year ago
  32. godorovg Group Title
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    because you typed 4v^2 while ago

    • one year ago
  33. godorovg Group Title
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    recall the problem here (2v^2+5v)(2v+5)

    • one year ago
  34. treydwg Group Title
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    yes that what I have

    • one year ago
  35. treydwg Group Title
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    2v(v+5)

    • one year ago
  36. treydwg Group Title
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    the (2v+5) is where im stuck

    • one year ago
  37. treydwg Group Title
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    what can I factor out of that?

    • one year ago
  38. godorovg Group Title
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    now 4v is right because 2v times 2v =4v^2 but that is not what is happening here. You have a power being times by V what is the power of the V? that power of the V is ^1 and when times 2v^2 time 2v = 4v^3

    • one year ago
  39. godorovg Group Title
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    so what happened here is we times the 2's to get 4 and v^2 + v^1 =V^3 see that

    • one year ago
  40. treydwg Group Title
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    let me look at that hold on

    • one year ago
  41. treydwg Group Title
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    ok I see it

    • one year ago
  42. treydwg Group Title
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    now how do I fix the last part?

    • one year ago
  43. godorovg Group Title
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    if you have a question plz ask me..

    • one year ago
  44. godorovg Group Title
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    factoring will not be in use unti we finish F.O.I.L

    • one year ago
  45. treydwg Group Title
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    I have (2v+5) how can I faactor this

    • one year ago
  46. godorovg Group Title
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    no you can not factor that..

    • one year ago
  47. treydwg Group Title
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    ok I see now so this is what I have after foil 4v^3+10v^2+35v

    • one year ago
  48. godorovg Group Title
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    now we can factor

    • one year ago
  49. treydwg Group Title
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    oooooooooh

    • one year ago
  50. treydwg Group Title
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    by grouping?

    • one year ago
  51. godorovg Group Title
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    no grouping there are no a like terms here

    • one year ago
  52. treydwg Group Title
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    I know but i was going to use 35v and try to make another number to group

    • one year ago
  53. godorovg Group Title
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    can not do that srry

    • one year ago
  54. treydwg Group Title
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    ok so wehre from here

    • one year ago
  55. treydwg Group Title
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    no GCF in common

    • one year ago
  56. godorovg Group Title
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    okay let us look at this 4v^3+10v^2+35v what is the same with all the numbers?

    • one year ago
  57. treydwg Group Title
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    v

    • one year ago
  58. godorovg Group Title
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    yes V so how many V's can be factored?

    • one year ago
  59. treydwg Group Title
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    1

    • one year ago
  60. treydwg Group Title
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    v(2v^2+10v+35)

    • one year ago
  61. godorovg Group Title
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    now look at the numbers what can each number be divided by?

    • one year ago
  62. treydwg Group Title
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    v(4v^2+10v+35)

    • one year ago
  63. godorovg Group Title
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    that is the answer it can not be factored any further

    • one year ago
  64. treydwg Group Title
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    ahhhhhhh! Thats my problem i want to always factor further :/

    • one year ago
  65. treydwg Group Title
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    Thank you

    • one year ago
  66. godorovg Group Title
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    treydwg here is a help for you, if you have done all the factoring right than find a number that divides in to the first and see if it works for example 2 will go ino 4 =2 2 will also go into 10 five times but here is a question for you will 2 divide even into 35?

    • one year ago
  67. godorovg Group Title
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    if the answer is no than you are finished..

    • one year ago
  68. treydwg Group Title
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    no it wont and that was my problem

    • one year ago
  69. treydwg Group Title
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    thanks

    • one year ago
  70. godorovg Group Title
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    welcome anytime

    • one year ago
  71. godorovg Group Title
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    before I leave any questions plz ask me

    • one year ago
  72. treydwg Group Title
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    thanks

    • one year ago
  73. treydwg Group Title
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    working on another

    • one year ago
  74. godorovg Group Title
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    If you need help I am here

    • one year ago
  75. treydwg Group Title
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    5x-3=14x+6 I got x=-1

    • one year ago
  76. godorovg Group Title
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    no

    • one year ago
  77. godorovg Group Title
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    5x-3=14x+6 get a like terms together so we x terms let us put the tgether like this 14x-5x=6-3 recall when a + or - crosses the equals sign it changes

    • one year ago
  78. treydwg Group Title
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    x=3/9??

    • one year ago
  79. godorovg Group Title
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    yes that is right

    • one year ago
  80. treydwg Group Title
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    ok i did that one a little wrong thank you

    • one year ago
  81. treydwg Group Title
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    now this one is throwing me off cuz the a^2 I have a^2=10-3a I got a^2=5/2

    • one year ago
  82. godorovg Group Title
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    no now think about this one? come you do it!!

    • one year ago
  83. treydwg Group Title
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    ok

    • one year ago
  84. godorovg Group Title
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    first off you can not a^2 = 10 -3a and come out with a^2=5/2 no..

    • one year ago
  85. godorovg Group Title
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    hint what happens to the problem when all nunbers are moved like this a^2+3a-10= what is this problem?

    • one year ago
  86. treydwg Group Title
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    um

    • one year ago
  87. godorovg Group Title
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    what did I say when a problem is set to zero is?

    • one year ago
  88. treydwg Group Title
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    nothing is on one side

    • one year ago
  89. treydwg Group Title
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    or they are all on one side rather

    • one year ago
  90. treydwg Group Title
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    have to factor?

    • one year ago
  91. godorovg Group Title
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    recall the problem a^2 = 10 -3a now look at the problem a^2+3a-10=

    • one year ago
  92. treydwg Group Title
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    0

    • one year ago
  93. treydwg Group Title
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    we have to find something in common

    • one year ago
  94. godorovg Group Title
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    so what type of problem is this? not factoring

    • one year ago
  95. treydwg Group Title
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    quadratic equation

    • one year ago
  96. godorovg Group Title
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    yes

    • one year ago
  97. treydwg Group Title
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    so i need to find out what two numbers product is 10 and sum is 3 right?

    • one year ago
  98. godorovg Group Title
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    yes but I will let you try this way.

    • one year ago
  99. treydwg Group Title
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    k

    • one year ago
  100. godorovg Group Title
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    don't forget the a^2

    • one year ago
  101. treydwg Group Title
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    a^2-2a+5a-10=0

    • one year ago
  102. treydwg Group Title
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    (a+5)(a-2)

    • one year ago
  103. godorovg Group Title
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    GREAT JOB!!!

    • one year ago
  104. treydwg Group Title
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    awesome thank you again!

    • one year ago
  105. treydwg Group Title
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    so the solution set is (a+5)(a-2)?

    • one year ago
  106. godorovg Group Title
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    now I want you to check this

    • one year ago
  107. treydwg Group Title
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    k how do I check?

    • one year ago
  108. godorovg Group Title
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    simply take this (a+5)(a-2) use F.O.I.L and see if you get this back a^2+3a-10=

    • one year ago
  109. godorovg Group Title
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    if you do than you are right..

    • one year ago
  110. treydwg Group Title
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    alright

    • one year ago
  111. godorovg Group Title
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    did you get it?

    • one year ago
  112. godorovg Group Title
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    treydwg if you need help let me know..

    • one year ago
  113. treydwg Group Title
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    now I got this one wrong? dont know why? r^2+2r-48 I got (r+8)(r-6)

    • one year ago
  114. treydwg Group Title
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    sorry working on another one

    • one year ago
  115. godorovg Group Title
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    which the - to 8 and try again

    • one year ago
  116. treydwg Group Title
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    but 6-8 = -2 and not 2

    • one year ago
  117. godorovg Group Title
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    try both -

    • one year ago
  118. treydwg Group Title
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    that gives me a +48 and not -48

    • one year ago
  119. treydwg Group Title
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    i am pretty sure im right but the computer counted it wrong??

    • one year ago
  120. godorovg Group Title
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    treydwg is this a test?

    • one year ago
  121. treydwg Group Title
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    yeah but I have three times to take

    • one year ago
  122. treydwg Group Title
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    I can not figure this out and i know im right!

    • one year ago
  123. treydwg Group Title
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    can you figure out why its wrong?

    • one year ago
  124. godorovg Group Title
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    give me a minute

    • one year ago
  125. treydwg Group Title
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    I have already taken the test. just reviewing results

    • one year ago
  126. godorovg Group Title
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    okay that is better, I can get big trouble for helping on tests..

    • one year ago
  127. godorovg Group Title
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    because you have taken it already no worries

    • one year ago
  128. treydwg Group Title
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    yes all done and really confused because my answers I beleive are correct. There are many more like that. Have you figured out why im wrong?

    • one year ago
  129. godorovg Group Title
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    working on it

    • one year ago
  130. treydwg Group Title
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    thank you

    • one year ago
  131. godorovg Group Title
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    okay try 24 times and see what happens and work it again

    • one year ago
  132. godorovg Group Title
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    2

    • one year ago
  133. godorovg Group Title
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    24 times 2?

    • one year ago
  134. treydwg Group Title
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    k

    • one year ago
  135. godorovg Group Title
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    friends are here

    • one year ago
  136. godorovg Group Title
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    brb for me I have company over will back soon

    • one year ago
  137. treydwg Group Title
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    thank you

    • one year ago
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