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64s^2+144s+81=0
(8s+9)^2=0
8s+9=0
8s=-9
s=-9/8

hmmm?

I think this problem is quadtradic

i believe it is too

thanks lol

so the solution set would be

I working on it

in this problem the first clue is being = 0 usally says Quad needs to be used.

What is the easier way of working out qUADRATIC without using the quad formula?

64^2 is a peferct square so that always tells that this will invole in a square root to slove

you could use a^2+B^2=c^2 as well

So I got -1.125, -1.125. Can I write -1.125^2. Or is this considered incorrect?

Ok i just wrote it twice. lets see if it counts it correct?

ok

what about 2v^2+7v+5 and I need tofactor by grouping?

I am at (2v^2+5v)(2v+5) and stuck

yes

where do I go from here?

in this problem we need to use F,.O.I .L

ok yes

so now take the 2v^2 and times to 2v what is the answer

4v^2

close try again

4v is right your power is wrong

where are you getting the 2v^2*2v?

because you typed 4v^2 while ago

recall the problem here (2v^2+5v)(2v+5)

yes that what I have

2v(v+5)

the (2v+5) is where im stuck

what can I factor out of that?

so what happened here is we times the 2's to get 4 and v^2 + v^1 =V^3 see that

let me look at that hold on

ok I see it

now how do I fix the last part?

if you have a question plz ask me..

factoring will not be in use unti we finish F.O.I.L

I have (2v+5) how can I faactor this

no you can not factor that..

ok I see now so this is what I have after foil
4v^3+10v^2+35v

now we can factor

oooooooooh

by grouping?

no grouping there are no a like terms here

I know but i was going to use 35v and try to make another number to group

can not do that srry

ok so wehre from here

no GCF in common

okay let us look at this 4v^3+10v^2+35v what is the same with all the numbers?

yes V so how many V's can be factored?

v(2v^2+10v+35)

now look at the numbers what can each number be divided by?

v(4v^2+10v+35)

that is the answer it can not be factored any further

ahhhhhhh! Thats my problem i want to always factor further :/

Thank you

if the answer is no than you are finished..

no it wont and that was my problem

thanks

welcome anytime

before I leave any questions plz ask me

thanks

working on another

If you need help I am here

5x-3=14x+6
I got x=-1

no

x=3/9??

yes that is right

ok i did that one a little wrong thank you

now this one is throwing me off cuz the a^2
I have a^2=10-3a
I got
a^2=5/2

no now think about this one? come you do it!!

ok

first off you can not a^2 = 10 -3a and come out with a^2=5/2 no..

um

what did I say when a problem is set to zero is?

nothing is on one side

or they are all on one side rather

have to factor?

recall the problem a^2 = 10 -3a now look at the problem a^2+3a-10=

we have to find something in common

so what type of problem is this? not factoring

quadratic equation

yes

so i need to find out what two numbers product is 10 and sum is 3 right?

yes but I will let you try this way.

don't forget the a^2

a^2-2a+5a-10=0

(a+5)(a-2)

GREAT JOB!!!

awesome thank you again!

so the solution set is (a+5)(a-2)?

now I want you to check this

k how do I check?

simply take this (a+5)(a-2) use F.O.I.L and see if you get this back a^2+3a-10=

if you do than you are right..

alright

did you get it?

treydwg if you need help let me know..

now I got this one wrong? dont know why?
r^2+2r-48
I got
(r+8)(r-6)

sorry working on another one

which the - to 8 and try again

but 6-8 = -2 and not 2

try both -

that gives me a +48 and not -48

i am pretty sure im right but the computer counted it wrong??

treydwg is this a test?

yeah but I have three times to take

I can not figure this out and i know im right!

can you figure out why its wrong?

give me a minute

I have already taken the test. just reviewing results

okay that is better, I can get big trouble for helping on tests..

because you have taken it already no worries

working on it

thank you

okay try 24 times and see what happens and work it again

24 times 2?

friends are here

brb for me I have company over will back soon

thank you