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LaddiusMaximus

@mertsj find the center and radius of the given circle. x^2+y^2-8x+12y-8=0

  • one year ago
  • one year ago

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  1. satellite73
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    aka complete the square (twice)

    • one year ago
  2. cwrw238
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    you can do this by converting your equation to the form (x - a)^2 + (y - b)^2 = r^2 where the center is (a,b) and radius = r you do this by a process called completing the square

    • one year ago
  3. LaddiusMaximus
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    ok so I have (x^2-8x)+(y^2+12y)=8

    • one year ago
  4. cwrw238
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    ok now convert x^6 - 8x and y^2 + 12y to the form (x - a)^2 - c

    • one year ago
  5. cwrw238
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    and (y- b)^2 - d

    • one year ago
  6. LaddiusMaximus
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    (x^2-8x+16)+(y^2+12y+36)=8+16+36

    • one year ago
  7. cwrw238
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    x^2 - 8x = (x - 4)^2 - 16

    • one year ago
  8. cwrw238
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    and y^2 + 12y = (y + 6)^2 - 36

    • one year ago
  9. cwrw238
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    so we get (x -4)^2 + (y + 6)^2 = 8+16+36 = 60

    • one year ago
  10. LaddiusMaximus
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    gotcha

    • one year ago
  11. cwrw238
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    good

    • one year ago
  12. cwrw238
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    compare the above withe standard equation and you'll get what you want

    • one year ago
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