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LaddiusMaximus
 3 years ago
@mertsj find the center and radius of the given circle. x^2+y^28x+12y8=0
LaddiusMaximus
 3 years ago
@mertsj find the center and radius of the given circle. x^2+y^28x+12y8=0

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0aka complete the square (twice)

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1you can do this by converting your equation to the form (x  a)^2 + (y  b)^2 = r^2 where the center is (a,b) and radius = r you do this by a process called completing the square

LaddiusMaximus
 3 years ago
Best ResponseYou've already chosen the best response.0ok so I have (x^28x)+(y^2+12y)=8

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1ok now convert x^6  8x and y^2 + 12y to the form (x  a)^2  c

LaddiusMaximus
 3 years ago
Best ResponseYou've already chosen the best response.0(x^28x+16)+(y^2+12y+36)=8+16+36

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1x^2  8x = (x  4)^2  16

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1and y^2 + 12y = (y + 6)^2  36

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1so we get (x 4)^2 + (y + 6)^2 = 8+16+36 = 60

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1compare the above withe standard equation and you'll get what you want
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