LaddiusMaximus
@mertsj find the center and radius of the given circle. x^2+y^2-8x+12y-8=0
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anonymous
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aka complete the square (twice)
cwrw238
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you can do this by converting your equation to the form
(x - a)^2 + (y - b)^2 = r^2
where the center is (a,b) and radius = r
you do this by a process called completing the square
LaddiusMaximus
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ok so I have (x^2-8x)+(y^2+12y)=8
cwrw238
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ok now convert x^6 - 8x and y^2 + 12y to the form (x - a)^2 - c
cwrw238
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and (y- b)^2 - d
LaddiusMaximus
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(x^2-8x+16)+(y^2+12y+36)=8+16+36
cwrw238
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x^2 - 8x =
(x - 4)^2 - 16
cwrw238
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and y^2 + 12y = (y + 6)^2 - 36
cwrw238
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so
we get
(x -4)^2 + (y + 6)^2 = 8+16+36 = 60
LaddiusMaximus
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gotcha
cwrw238
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good
cwrw238
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compare the above withe standard equation and you'll get what you want