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 one year ago
@mertsj find the center and radius of the given circle. x^2+y^28x+12y8=0
 one year ago
@mertsj find the center and radius of the given circle. x^2+y^28x+12y8=0

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satellite73
 one year ago
Best ResponseYou've already chosen the best response.0aka complete the square (twice)

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1you can do this by converting your equation to the form (x  a)^2 + (y  b)^2 = r^2 where the center is (a,b) and radius = r you do this by a process called completing the square

LaddiusMaximus
 one year ago
Best ResponseYou've already chosen the best response.0ok so I have (x^28x)+(y^2+12y)=8

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1ok now convert x^6  8x and y^2 + 12y to the form (x  a)^2  c

LaddiusMaximus
 one year ago
Best ResponseYou've already chosen the best response.0(x^28x+16)+(y^2+12y+36)=8+16+36

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1x^2  8x = (x  4)^2  16

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1and y^2 + 12y = (y + 6)^2  36

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1so we get (x 4)^2 + (y + 6)^2 = 8+16+36 = 60

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1compare the above withe standard equation and you'll get what you want
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