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@mertsj find the center and radius of the given circle. x^2+y^28x+12y8=0
 one year ago
 one year ago
@mertsj find the center and radius of the given circle. x^2+y^28x+12y8=0
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.0
aka complete the square (twice)
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
you can do this by converting your equation to the form (x  a)^2 + (y  b)^2 = r^2 where the center is (a,b) and radius = r you do this by a process called completing the square
 one year ago

LaddiusMaximusBest ResponseYou've already chosen the best response.0
ok so I have (x^28x)+(y^2+12y)=8
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
ok now convert x^6  8x and y^2 + 12y to the form (x  a)^2  c
 one year ago

LaddiusMaximusBest ResponseYou've already chosen the best response.0
(x^28x+16)+(y^2+12y+36)=8+16+36
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
x^2  8x = (x  4)^2  16
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
and y^2 + 12y = (y + 6)^2  36
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
so we get (x 4)^2 + (y + 6)^2 = 8+16+36 = 60
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
compare the above withe standard equation and you'll get what you want
 one year ago
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