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Pinky1234

  • 2 years ago

Can anyone help me with this question? Y^2tan(x)=x. Find dy/dx.

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  1. malcolm11235
    • 2 years ago
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    you could solve for y then differentiate that way or you could do implicit if you wanted.

  2. cwrw238
    • 2 years ago
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    is this |dw:1359321531751:dw|

  3. Pinky1234
    • 2 years ago
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    yeah we need to do implicit but can you go through with me because this is a new course for me and I am having really tough time with this. I have couple more questions then I ll try by myself.

  4. Pinky1234
    • 2 years ago
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    Yes thats right

  5. Pinky1234
    • 2 years ago
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    looks like no one wants to help me here.

  6. malcolm11235
    • 2 years ago
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    it goes something like |dw:1359321813888:dw|

  7. malcolm11235
    • 2 years ago
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    so then solve for y'

  8. malcolm11235
    • 2 years ago
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    double check what the derivative of tanx is too, i'm not 100% sure

  9. Pinky1234
    • 2 years ago
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    ahan ok and I also have an answer for this that my professor gave which is: \[(1-y ^{2}\sec ^{2}x)/2y \tan (x)\]

  10. malcolm11235
    • 2 years ago
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    that's what you'll get once you rearrage and solve for y'

  11. Pinky1234
    • 2 years ago
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    derivative of tanx is \[\sec ^{2}x\]

  12. malcolm11235
    • 2 years ago
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    okay. now you know how to do it.

  13. Pinky1234
    • 2 years ago
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    no still not sure

  14. cwrw238
    • 2 years ago
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    sorry Pinky - i got called away malcolm is explaining it well

  15. Pinky1234
    • 2 years ago
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    can we go through till the answer

  16. Pinky1234
    • 2 years ago
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    its ok cwrw238

  17. malcolm11235
    • 2 years ago
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    i did go through to the answer. i just didn't rearrange it to solve for dy/dx= y', which is basic algebra, a prerequisite for your calculus course.

  18. Pinky1234
    • 2 years ago
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    hmmmm but can you please also show me to rearrange it if its possible for you?

  19. malcolm11235
    • 2 years ago
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    oops forgot the tanx in there but you just move the one term to the other side then divide by 2ytanx

  20. malcolm11235
    • 2 years ago
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    that last drawing was completely wrong, i don't have time to write it out. it's really basic stuff you should know.

  21. malcolm11235
    • 2 years ago
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    that's not the answr there. thats me saying that y' = dy/dx in case you didn't know that so in the equation, y' = dy/dx

  22. Pinky1234
    • 2 years ago
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    ok

  23. malcolm11235
    • 2 years ago
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    |dw:1359322857339:dw|

  24. malcolm11235
    • 2 years ago
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    that's your full solution. don't come on here and expect people to add 1+1 for you.

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