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Pinky1234
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Can anyone help me with this question? Y^2tan(x)=x. Find dy/dx.
 one year ago
 one year ago
Pinky1234 Group Title
Can anyone help me with this question? Y^2tan(x)=x. Find dy/dx.
 one year ago
 one year ago

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malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
you could solve for y then differentiate that way or you could do implicit if you wanted.
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
is this dw:1359321531751:dw
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
yeah we need to do implicit but can you go through with me because this is a new course for me and I am having really tough time with this. I have couple more questions then I ll try by myself.
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
Yes thats right
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
looks like no one wants to help me here.
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
it goes something like dw:1359321813888:dw
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
so then solve for y'
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
double check what the derivative of tanx is too, i'm not 100% sure
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
ahan ok and I also have an answer for this that my professor gave which is: \[(1y ^{2}\sec ^{2}x)/2y \tan (x)\]
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
that's what you'll get once you rearrage and solve for y'
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
derivative of tanx is \[\sec ^{2}x\]
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
okay. now you know how to do it.
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
no still not sure
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
sorry Pinky  i got called away malcolm is explaining it well
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
can we go through till the answer
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
its ok cwrw238
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
i did go through to the answer. i just didn't rearrange it to solve for dy/dx= y', which is basic algebra, a prerequisite for your calculus course.
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.0
hmmmm but can you please also show me to rearrange it if its possible for you?
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
oops forgot the tanx in there but you just move the one term to the other side then divide by 2ytanx
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
that last drawing was completely wrong, i don't have time to write it out. it's really basic stuff you should know.
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
that's not the answr there. thats me saying that y' = dy/dx in case you didn't know that so in the equation, y' = dy/dx
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
dw:1359322857339:dw
 one year ago

malcolm11235 Group TitleBest ResponseYou've already chosen the best response.0
that's your full solution. don't come on here and expect people to add 1+1 for you.
 one year ago
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