anonymous
  • anonymous
Can anyone help me with this question? Y^2tan(x)=x. Find dy/dx.
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
you could solve for y then differentiate that way or you could do implicit if you wanted.
cwrw238
  • cwrw238
is this |dw:1359321531751:dw|
anonymous
  • anonymous
yeah we need to do implicit but can you go through with me because this is a new course for me and I am having really tough time with this. I have couple more questions then I ll try by myself.

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anonymous
  • anonymous
Yes thats right
anonymous
  • anonymous
looks like no one wants to help me here.
anonymous
  • anonymous
it goes something like |dw:1359321813888:dw|
anonymous
  • anonymous
so then solve for y'
anonymous
  • anonymous
double check what the derivative of tanx is too, i'm not 100% sure
anonymous
  • anonymous
ahan ok and I also have an answer for this that my professor gave which is: \[(1-y ^{2}\sec ^{2}x)/2y \tan (x)\]
anonymous
  • anonymous
that's what you'll get once you rearrage and solve for y'
anonymous
  • anonymous
derivative of tanx is \[\sec ^{2}x\]
anonymous
  • anonymous
okay. now you know how to do it.
anonymous
  • anonymous
no still not sure
cwrw238
  • cwrw238
sorry Pinky - i got called away malcolm is explaining it well
anonymous
  • anonymous
can we go through till the answer
anonymous
  • anonymous
its ok cwrw238
anonymous
  • anonymous
i did go through to the answer. i just didn't rearrange it to solve for dy/dx= y', which is basic algebra, a prerequisite for your calculus course.
anonymous
  • anonymous
hmmmm but can you please also show me to rearrange it if its possible for you?
anonymous
  • anonymous
oops forgot the tanx in there but you just move the one term to the other side then divide by 2ytanx
anonymous
  • anonymous
that last drawing was completely wrong, i don't have time to write it out. it's really basic stuff you should know.
anonymous
  • anonymous
that's not the answr there. thats me saying that y' = dy/dx in case you didn't know that so in the equation, y' = dy/dx
anonymous
  • anonymous
ok
anonymous
  • anonymous
|dw:1359322857339:dw|
anonymous
  • anonymous
that's your full solution. don't come on here and expect people to add 1+1 for you.

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