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abb0t
 one year ago
Best ResponseYou've already chosen the best response.0How about you find the limit: \[\lim_{x \rightarrow 0}\left( \frac{ 3 }{ 2x }\frac{ 3 }{ 2x } \right)\]

MoonlitFate
 one year ago
Best ResponseYou've already chosen the best response.2\[\lim x > \frac{ 3\pi }{ 4 } \] \[[\theta * \tan(\theta)]\]

MoonlitFate
 one year ago
Best ResponseYou've already chosen the best response.2@abb0t  Challenge accepted. :p

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0tangent, and almost every function you know, is continuous on its domain so find \(\tan(\frac{3\pi}{4})\)

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0HAHA. Right on @MoonlitFate that's the spirit :D

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0of course 0 is not in the domain of @abb0t question, so that method will clearly not work for that one

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0and so \(\frac{3\pi}{4}\times 1=\frac{3\pi}{4}\) is your answer

MoonlitFate
 one year ago
Best ResponseYou've already chosen the best response.2@satellite73  That's what I got; I just wanted to make sure I was right! :)

MoonlitFate
 one year ago
Best ResponseYou've already chosen the best response.2All right @abb0t now it's time for that problem.

MoonlitFate
 one year ago
Best ResponseYou've already chosen the best response.2@abb0t  There is no limit. :) The limit approaches different values from both sides of 0.
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