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LaddiusMaximus
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Find the center of and radius of the given circle x^2+y^212x2y12=0
 one year ago
 one year ago
LaddiusMaximus Group Title
Find the center of and radius of the given circle x^2+y^212x2y12=0
 one year ago
 one year ago

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cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
complete the squares again for the x and y terms and compare with standard equation of a circle
 one year ago

LaddiusMaximus Group TitleBest ResponseYou've already chosen the best response.0
ok I got down to (x^26x+36)+(y^2y+1)=12+36+1
 one year ago

Luis_Rivera Group TitleBest ResponseYou've already chosen the best response.0
x^(2)+y^(2)12x2y12=0 x^(2)12x+y^(2)2y=12 (x6)^(2)+(y1)^(2)=12+36+1 (x6)^(2)+(y1)^(2)=49 (xh)^(2)+(yk)^(2)=r^(2) Center: (6,1)_Radius: 7
 one year ago
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