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LaddiusMaximus

  • 3 years ago

Find the center of and radius of the given circle x^2+y^2-12x-2y-12=0

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  1. cwrw238
    • 3 years ago
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    complete the squares again for the x and y terms and compare with standard equation of a circle

  2. LaddiusMaximus
    • 3 years ago
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    ok I got down to (x^2-6x+36)+(y^2-y+1)=12+36+1

  3. Luis_Rivera
    • 3 years ago
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    x^(2)+y^(2)-12x-2y-12=0 x^(2)-12x+y^(2)-2y=12 (x-6)^(2)+(y-1)^(2)=12+36+1 (x-6)^(2)+(y-1)^(2)=49 (x-h)^(2)+(y-k)^(2)=r^(2) Center: (6,1)_Radius: 7

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