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skapat

  • 2 years ago

Can anyone help me out with this problem: A ball is thrown vertically upward with initial velocity v. Find the maximum height H of the ball as a function of v. Then find the initial velocity v required to achieve a height of H.

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  1. Shadowys
    • 2 years ago
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    we'll just use the eq, \(v^2 = u^2 +2aS\), since u=0, a=-g,(since it is opposite direction of v), rearranging gives \(S=\frac{v^2}{2g}\)

  2. Shadowys
    • 2 years ago
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    where S=H

  3. skapat
    • 2 years ago
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    ive arrived at this answer too...however when i submitted it...it said that g was not defined in this context

  4. skapat
    • 2 years ago
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    is there any way to answer this in terms of H and v only?

  5. Shadowys
    • 2 years ago
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    or, you can just sub g=10 into it

  6. skapat
    • 2 years ago
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    thats what i would think so too. but it still says that answer is incorrect

  7. Shadowys
    • 2 years ago
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    oh oh. sorry. my mistake. it's initial velocity, not end velocity. since v=0, \(u=\sqrt{2gH}=\sqrt{19.8H}\)

  8. skapat
    • 2 years ago
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    tried that one too unfortunately....im not sure what they looking for

  9. Shadowys
    • 2 years ago
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    dang==then i have no idea what they want

  10. skapat
    • 2 years ago
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    thanks for trying to help though. ...its very much appreciated :)

  11. Shadowys
    • 2 years ago
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    you're welcome :)

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