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skapat
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Can anyone help me out with this problem: A ball is thrown vertically upward with initial velocity v. Find the maximum height H of the ball as a function of v. Then find the initial velocity v required to achieve a height of H.
 one year ago
 one year ago
skapat Group Title
Can anyone help me out with this problem: A ball is thrown vertically upward with initial velocity v. Find the maximum height H of the ball as a function of v. Then find the initial velocity v required to achieve a height of H.
 one year ago
 one year ago

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Shadowys Group TitleBest ResponseYou've already chosen the best response.0
we'll just use the eq, \(v^2 = u^2 +2aS\), since u=0, a=g,(since it is opposite direction of v), rearranging gives \(S=\frac{v^2}{2g}\)
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
where S=H
 one year ago

skapat Group TitleBest ResponseYou've already chosen the best response.0
ive arrived at this answer too...however when i submitted it...it said that g was not defined in this context
 one year ago

skapat Group TitleBest ResponseYou've already chosen the best response.0
is there any way to answer this in terms of H and v only?
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
or, you can just sub g=10 into it
 one year ago

skapat Group TitleBest ResponseYou've already chosen the best response.0
thats what i would think so too. but it still says that answer is incorrect
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
oh oh. sorry. my mistake. it's initial velocity, not end velocity. since v=0, \(u=\sqrt{2gH}=\sqrt{19.8H}\)
 one year ago

skapat Group TitleBest ResponseYou've already chosen the best response.0
tried that one too unfortunately....im not sure what they looking for
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
dang==then i have no idea what they want
 one year ago

skapat Group TitleBest ResponseYou've already chosen the best response.0
thanks for trying to help though. ...its very much appreciated :)
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
you're welcome :)
 one year ago
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