Can anyone help me out with this problem: A ball is thrown vertically upward with initial velocity v. Find the maximum height H of the ball as a function of v. Then find the initial velocity v required to achieve a height of H.

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we'll just use the eq, \(v^2 = u^2 +2aS\), since u=0, a=-g,(since it is opposite direction of v), rearranging gives \(S=\frac{v^2}{2g}\)

where S=H

ive arrived at this answer too...however when i submitted it...it said that g was not defined in this context

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