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1) lim x-> 1 (x^2 - 1)/(x + 2)
2) lim x-> 1 (x^2 + 1)/(x - 1)

@UnkleRhaukus umm can u help?

1) \[\lim\limits_ {x\to1}\frac{ x^2 - 1}{x + 2}\]
what happens when we put x=1 into the fraction

hmm its becomes 0/3?

yeah, do you know what that simplifies to ?

umm 0?

correct,

okay so how would i describe it?

can you fill in the table |dw:1359329822568:dw|

yes i can

okay let me try this

so for the -2 one i'm dividing -5 to 0 so will it be -5/0 since i cant divide that?

ok so i got |dw:1359330562610:dw|

so did i get it?

|dw:1359330502446:dw|

are u there?

ok

how about now? |dw:1359331215777:dw|

umm are u there?

okay

so then i draw the graph? right ?

yeah not plot those points |dw:1359331297137:dw|

not*now

ok

|dw:1359331448238:dw|
maybe i should have chosen some better x points

what are the question marks and the lines?

ive put question marks for for the x=-2, y=-5/0 bit

ohh okay

|dw:1359331760380:dw|

so its a curve?

if i chose better x values
we would have got something like this

okay

so that will be the end of the problem?

|dw:1359332271558:dw|

|dw:1359332425565:dw|

|dw:1359332578040:dw|

ok so this is the final graph?

okay

|dw:1359332784659:dw|

ohh ok i get it

okay

i hope i haven't confused you too much

noo u havent so i'll do the same this with lim x-> 1 (x^2 + 1)/(x -1)

another way of saying the value is undefined is to say the limit does not exist

okay

so i'll do the same for lim x-> 1 (x^2 + 1)/(x -1)?

yeah, i would use
x =-5,-4,-3,-2,-1,0,2,3,4,5
this time

ok thanks!! :)

ok im off, good luck

hey so i did it is this correct? |dw:1359335654116:dw| |dw:1359335759751:dw|

@satellite73 can u help with this?