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Use numerical and graphical evidence to conjecture value(s) for the limits, if they exist. If not, describe what is happening at x = a graphically.
 one year ago
 one year ago
Use numerical and graphical evidence to conjecture value(s) for the limits, if they exist. If not, describe what is happening at x = a graphically.
 one year ago
 one year ago

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onegirlBest ResponseYou've already chosen the best response.0
1) lim x> 1 (x^2  1)/(x + 2) 2) lim x> 1 (x^2 + 1)/(x  1)
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
@UnkleRhaukus umm can u help?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
1) \[\lim\limits_ {x\to1}\frac{ x^2  1}{x + 2}\] what happens when we put x=1 into the fraction
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
yeah, do you know what that simplifies to ?
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
okay so how would i describe it?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
can you fill in the table dw:1359329822568:dw
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
so for the 2 one i'm dividing 5 to 0 so will it be 5/0 since i cant divide that?
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
ok so i got dw:1359330562610:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dw:1359330502446:dw
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
how about now? dw:1359331215777:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
(sorry my internet cut out for a moment there) um you got most of them right the first time but check the case when x=1 agian dw:1359331049113:dw
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
so then i draw the graph? right ?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
yeah not plot those points dw:1359331297137:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dw:1359331448238:dw maybe i should have chosen some better x points
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
what are the question marks and the lines?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
ive put question marks for for the x=2, y=5/0 bit
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dw:1359331760380:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
if i chose better x values we would have got something like this
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
so that will be the end of the problem?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dw:1359332271558:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dw:1359332425565:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dw:1359332578040:dw
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
ok so this is the final graph?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
this shape is called a hyperbola at x=2 y is undefined, this is because if we look at the graph is should be +∞ and also ∞ but it can't be more than one point we call this a vertical Asymptote
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dw:1359332784659:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
to describe what is happening at x=a if \(a < 2\) the value will be on the bottom curve if \(a = 2\) the value is undefined if \(a >2\) the value will be on the top curve
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
__________ for 2) \[ \lim\limits_{x\to 1} \frac{x^2 + 1}{x  1} \] the value is undefined as we are trying to taking the limit at the asymptote
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
i hope i haven't confused you too much
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
noo u havent so i'll do the same this with lim x> 1 (x^2 + 1)/(x 1)
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
another way of saying the value is undefined is to say the limit does not exist
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
so i'll do the same for lim x> 1 (x^2 + 1)/(x 1)?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
yeah, i would use x =5,4,3,2,1,0,2,3,4,5 this time
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
ok im off, good luck
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
hey so i did it is this correct? dw:1359335654116:dw dw:1359335759751:dw
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
@satellite73 can u help with this?
 one year ago
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