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 one year ago
Use numerical and graphical evidence to conjecture value(s) for the limits, if they exist. If not, describe what is happening at x = a graphically.
 one year ago
Use numerical and graphical evidence to conjecture value(s) for the limits, if they exist. If not, describe what is happening at x = a graphically.

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onegirl
 one year ago
Best ResponseYou've already chosen the best response.01) lim x> 1 (x^2  1)/(x + 2) 2) lim x> 1 (x^2 + 1)/(x  1)

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus umm can u help?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.11) \[\lim\limits_ {x\to1}\frac{ x^2  1}{x + 2}\] what happens when we put x=1 into the fraction

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1yeah, do you know what that simplifies to ?

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0okay so how would i describe it?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1can you fill in the table dw:1359329822568:dw

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so for the 2 one i'm dividing 5 to 0 so will it be 5/0 since i cant divide that?

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0ok so i got dw:1359330562610:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359330502446:dw

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0how about now? dw:1359331215777:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1(sorry my internet cut out for a moment there) um you got most of them right the first time but check the case when x=1 agian dw:1359331049113:dw

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so then i draw the graph? right ?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1yeah not plot those points dw:1359331297137:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359331448238:dw maybe i should have chosen some better x points

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0what are the question marks and the lines?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1ive put question marks for for the x=2, y=5/0 bit

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359331760380:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1if i chose better x values we would have got something like this

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so that will be the end of the problem?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359332271558:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359332425565:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359332578040:dw

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0ok so this is the final graph?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1this shape is called a hyperbola at x=2 y is undefined, this is because if we look at the graph is should be +∞ and also ∞ but it can't be more than one point we call this a vertical Asymptote

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359332784659:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1to describe what is happening at x=a if \(a < 2\) the value will be on the bottom curve if \(a = 2\) the value is undefined if \(a >2\) the value will be on the top curve

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1__________ for 2) \[ \lim\limits_{x\to 1} \frac{x^2 + 1}{x  1} \] the value is undefined as we are trying to taking the limit at the asymptote

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1i hope i haven't confused you too much

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0noo u havent so i'll do the same this with lim x> 1 (x^2 + 1)/(x 1)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1another way of saying the value is undefined is to say the limit does not exist

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so i'll do the same for lim x> 1 (x^2 + 1)/(x 1)?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1yeah, i would use x =5,4,3,2,1,0,2,3,4,5 this time

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1ok im off, good luck

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0hey so i did it is this correct? dw:1359335654116:dw dw:1359335759751:dw

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 can u help with this?
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