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seancashmere
 3 years ago
what is the antiderivative of f'(x)=4/(1x^2)^(1/2) if f(1/2) = 1?
seancashmere
 3 years ago
what is the antiderivative of f'(x)=4/(1x^2)^(1/2) if f(1/2) = 1?

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seancashmere
 3 years ago
Best ResponseYou've already chosen the best response.0so it's the stupid chain rule that's messing me up. I have no clue how to find this. Wolfram Alpha throws sin inverse at me!

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.1Chain rule? Then, does that mean you are referring to derivatives?

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.1B/c the antiderivative of that would technically be arcsine.

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1integrate using x=sin u

seancashmere
 3 years ago
Best ResponseYou've already chosen the best response.0well, I took a stab at it and got 8(1/21/3(x)^3)^(1/2) but when I tried to check it, the chain rule throws it all off! We haven't gotten to integrating yet! I don't even know what that means.

seancashmere
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, I guess I have to review this chapter in my textbook. I thought this homework assignment would only be based on what we did in class....

seancashmere
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, I get it now. It's an identity. The d/dx of sin inverse is 1/(1x)^2. Thanks again!
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