anonymous
  • anonymous
what is the antiderivative of f'(x)=4/(1-x^2)^(1/2) if f(1/2) = 1?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
so it's the stupid chain rule that's messing me up. I have no clue how to find this. Wolfram Alpha throws sin inverse at me!
abb0t
  • abb0t
Chain rule? Then, does that mean you are referring to derivatives?
abb0t
  • abb0t
B/c the anti-derivative of that would technically be arcsine.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

slaaibak
  • slaaibak
integrate using x=sin u
anonymous
  • anonymous
well, I took a stab at it and got 8(1/2-1/3(x)^3)^(-1/2) but when I tried to check it, the chain rule throws it all off! We haven't gotten to integrating yet! I don't even know what that means.
anonymous
  • anonymous
Okay, I guess I have to review this chapter in my textbook. I thought this homework assignment would only be based on what we did in class....
anonymous
  • anonymous
Yes, I get it now. It's an identity. The d/dx of sin inverse is 1/(1-x)^2. Thanks again!

Looking for something else?

Not the answer you are looking for? Search for more explanations.