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what is the antiderivative of f'(x)=4/(1x^2)^(1/2) if f(1/2) = 1?
 one year ago
 one year ago
what is the antiderivative of f'(x)=4/(1x^2)^(1/2) if f(1/2) = 1?
 one year ago
 one year ago

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seancashmereBest ResponseYou've already chosen the best response.0
so it's the stupid chain rule that's messing me up. I have no clue how to find this. Wolfram Alpha throws sin inverse at me!
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
Chain rule? Then, does that mean you are referring to derivatives?
 one year ago

abb0tBest ResponseYou've already chosen the best response.1
B/c the antiderivative of that would technically be arcsine.
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
integrate using x=sin u
 one year ago

seancashmereBest ResponseYou've already chosen the best response.0
well, I took a stab at it and got 8(1/21/3(x)^3)^(1/2) but when I tried to check it, the chain rule throws it all off! We haven't gotten to integrating yet! I don't even know what that means.
 one year ago

seancashmereBest ResponseYou've already chosen the best response.0
Okay, I guess I have to review this chapter in my textbook. I thought this homework assignment would only be based on what we did in class....
 one year ago

seancashmereBest ResponseYou've already chosen the best response.0
Yes, I get it now. It's an identity. The d/dx of sin inverse is 1/(1x)^2. Thanks again!
 one year ago
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