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\[y=\cos(\frac{ 1-e ^{2x} }{ 1+e ^{2x} })\]

anyone? anyone? bueller? bueller? lmfao

lol c:

or do i differentiate with the chain rule and division rule?

Yes you do that :)
Sorry I was waiting cuz I thought Canadian was going to explain it.

wait which one do i do? lol

The second one ^^

Ahh I'm smarter than i give myself credit for

lol

minus sign of all that mess times the derivative of all that mess

don't forget the minus sign

Woops, sorry i just did a bunch of integrals... blah :3

Oh he was typing after all....

lol go ahead zepdrix Canadian doesn't use the equation and it just hurts my eyes and confuses me.

<:o

Looks like we need to apply the quotient rule to the blue part yes? :o

ok gotcha give me a minute let me see if I can figure it out

woo hoo!!~! i got it right!!

Yayyy betty \c:/ boop boopy doop! or however that goes :3 ...

*also

:o