ineedyouubiebs
Write an equation of a line that passes through the given point and is perpendicular to the given line in slope intercept form (4,-5) y=2x+3
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jim_thompson5910
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what is the slope of y = 2x+3
ineedyouubiebs
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2x
jim_thompson5910
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close, it's just 2
jim_thompson5910
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that's the same as 2/1
ineedyouubiebs
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my bad sorry.wouldnt it be -2/1 ??
jim_thompson5910
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to find the perpendicular slope, just flip the fraction and flip the sign
so flip the fraction to go from 2/1 to 1/2
then flip the sign to go from +1/2 to -1/2
this means that the perpendicular slope is -1/2
jim_thompson5910
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now you need to find the equation of the line that
a) has the slope of -1/2
and
b) goes through the point (4, -5)
ineedyouubiebs
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AHHH!! I get it !!the new equation will be y=-1/2+3 now right?
jim_thompson5910
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no, that's not correct
ineedyouubiebs
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no?
jim_thompson5910
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you start with y = mx+b and you plug in the slope (-1/2) and the given point (4,-5)
y = mx+b
y = (-1/2)x + b ... plug in the slope m = -1/2
-5 = (-1/2)(4) + b ... plug in x = 4 and y = -5
-5 = -2 + b
solve for b
ineedyouubiebs
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b=-3
jim_thompson5910
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good, so the equation of the perpendicular line is \[\Large y = -\frac{1}{2}x - 3\]
ineedyouubiebs
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Thank you so much!:D
jim_thompson5910
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you're welcome