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ineedyouubiebs

  • 2 years ago

Write an equation of a line that passes through the given point and is perpendicular to the given line in slope intercept form (4,-5) y=2x+3

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  1. jim_thompson5910
    • 2 years ago
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    what is the slope of y = 2x+3

  2. ineedyouubiebs
    • 2 years ago
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    2x

  3. jim_thompson5910
    • 2 years ago
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    close, it's just 2

  4. jim_thompson5910
    • 2 years ago
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    that's the same as 2/1

  5. ineedyouubiebs
    • 2 years ago
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    my bad sorry.wouldnt it be -2/1 ??

  6. jim_thompson5910
    • 2 years ago
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    to find the perpendicular slope, just flip the fraction and flip the sign so flip the fraction to go from 2/1 to 1/2 then flip the sign to go from +1/2 to -1/2 this means that the perpendicular slope is -1/2

  7. jim_thompson5910
    • 2 years ago
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    now you need to find the equation of the line that a) has the slope of -1/2 and b) goes through the point (4, -5)

  8. ineedyouubiebs
    • 2 years ago
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    AHHH!! I get it !!the new equation will be y=-1/2+3 now right?

  9. jim_thompson5910
    • 2 years ago
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    no, that's not correct

  10. ineedyouubiebs
    • 2 years ago
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    no?

  11. jim_thompson5910
    • 2 years ago
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    you start with y = mx+b and you plug in the slope (-1/2) and the given point (4,-5) y = mx+b y = (-1/2)x + b ... plug in the slope m = -1/2 -5 = (-1/2)(4) + b ... plug in x = 4 and y = -5 -5 = -2 + b solve for b

  12. ineedyouubiebs
    • 2 years ago
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    b=-3

  13. jim_thompson5910
    • 2 years ago
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    good, so the equation of the perpendicular line is \[\Large y = -\frac{1}{2}x - 3\]

  14. ineedyouubiebs
    • 2 years ago
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    Thank you so much!:D

  15. jim_thompson5910
    • 2 years ago
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    you're welcome

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