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ineedyouubiebs
 2 years ago
Write an equation of a line that passes through the given point and is perpendicular to the given line in slope intercept form (4,5) y=2x+3
ineedyouubiebs
 2 years ago
Write an equation of a line that passes through the given point and is perpendicular to the given line in slope intercept form (4,5) y=2x+3

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jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0what is the slope of y = 2x+3

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0close, it's just 2

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0that's the same as 2/1

ineedyouubiebs
 2 years ago
Best ResponseYou've already chosen the best response.1my bad sorry.wouldnt it be 2/1 ??

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0to find the perpendicular slope, just flip the fraction and flip the sign so flip the fraction to go from 2/1 to 1/2 then flip the sign to go from +1/2 to 1/2 this means that the perpendicular slope is 1/2

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0now you need to find the equation of the line that a) has the slope of 1/2 and b) goes through the point (4, 5)

ineedyouubiebs
 2 years ago
Best ResponseYou've already chosen the best response.1AHHH!! I get it !!the new equation will be y=1/2+3 now right?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0no, that's not correct

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0you start with y = mx+b and you plug in the slope (1/2) and the given point (4,5) y = mx+b y = (1/2)x + b ... plug in the slope m = 1/2 5 = (1/2)(4) + b ... plug in x = 4 and y = 5 5 = 2 + b solve for b

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0good, so the equation of the perpendicular line is \[\Large y = \frac{1}{2}x  3\]

ineedyouubiebs
 2 years ago
Best ResponseYou've already chosen the best response.1Thank you so much!:D

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0you're welcome
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