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Write an equation of a line that passes through the given point and is perpendicular to the given line in slope intercept form (4,-5) y=2x+3

Algebra
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what is the slope of y = 2x+3
2x
close, it's just 2

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Other answers:

that's the same as 2/1
my bad sorry.wouldnt it be -2/1 ??
to find the perpendicular slope, just flip the fraction and flip the sign so flip the fraction to go from 2/1 to 1/2 then flip the sign to go from +1/2 to -1/2 this means that the perpendicular slope is -1/2
now you need to find the equation of the line that a) has the slope of -1/2 and b) goes through the point (4, -5)
AHHH!! I get it !!the new equation will be y=-1/2+3 now right?
no, that's not correct
no?
you start with y = mx+b and you plug in the slope (-1/2) and the given point (4,-5) y = mx+b y = (-1/2)x + b ... plug in the slope m = -1/2 -5 = (-1/2)(4) + b ... plug in x = 4 and y = -5 -5 = -2 + b solve for b
b=-3
good, so the equation of the perpendicular line is \[\Large y = -\frac{1}{2}x - 3\]
Thank you so much!:D
you're welcome

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