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how would you start the conversion would you do this |dw:1359337417354:dw|

im really confused as to how to do this conversion although i thought i had this stuff down :(

thats how i did the above conversion btw |dw:1359337550325:dw|

this if from my chemistry book all its asking to do is conversion

the formula is given just have to apply it and i have no clue

1.554 × 103 kJ ?
Is it 1.554 x 10^3 kJ.

yes

Okay.

i converted it to J thats why its 1.554*10^6 in my attempt

SO it's this?
\[1.554\times 10^6 \times \frac{ kgm^x }{ s^x }\]

ill post a print screen of the problem

sorry i should have probably posted the problem earlier

Okay, Do you have the correct answer? Like an answer sheet or something?

no i cant get the solution it would be 0 points after that :)

i can try random answer to see if it gives me hint

i have 5 attempts to get it right

I got some weird number. I got
\[4.564\times 10^{13}\]

That's to 4 significant numbers

ok im gonna try that see if its right

nope

No it's not.

not the right answer

Don't you have to find the mass of the water?

no we dont

we are just trying to do some conversion this is Chapter 2 should be some basic stuff

Wait mate. You're trying to find the change in mass?

yes

the question does say that :P

Man, heat of combustion keeps popping up in my head for some reason.

so would you do something like mole so 12.096/1.008 and 96/16 and get the value in mole form

yea its nothing complicated like that i have just started to dip into basic chemisty

What year/grade is this?

first year chemisty college not incredibly basic but 101

so would you |dw:1359339344388:dw|

and square the speed of light

then change from g to kg by dividing by 1000 or would you conver to mole

so heres what im doing right now since m = e/c^2

first i change the 10.965/1.001 and 87/16 to convert it to mole

then i divide 1554000/2.9*10^8

E should be in joules, m in kilograms and c in meters per second

i really am not getting this

\[\frac{1.554\times 10^6}{(3\times 10^8)^2}=.1727 \times 10^{-10} kg\]

yea ive done that before is that just it?

then you convert from kg to g?

Multiply by 1000

nope thats not it

oops i messed up

hold on i forgot to square

\[.1727 \times 10^{-10}kg=.1727 \times 10^{-7}g = 1.727 \times 10^{-8}g\]

yea but i ran out of turns and that was the answe r:(

well thanks a lot for your help

What was the answer?

1.72*10^-8

yep. I thought so.

yea im gonna have to hit the books again and learn why i didnt get it thanks a lot

yw