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sat_chen

It was pointed out that mass and energy are alternate aspects of a single entity called mass-energy. The relationship between these two physical quantities is Einstein's equation, E = mc2, where E is energy, m is mass, and c is the speed of light. In a combustion experiment, it was found that 10.965 g of hydrogen molecules combined with 87.000 g of oxygen molecules to form water and released 1.554 × 103 kJ of heat. Use Einstein's equation to calculate the corresponding mass change in this process,

  • one year ago
  • one year ago

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  1. sat_chen
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    how would you start the conversion would you do this |dw:1359337417354:dw|

    • one year ago
  2. sat_chen
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    im really confused as to how to do this conversion although i thought i had this stuff down :(

    • one year ago
  3. sat_chen
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    thats how i did the above conversion btw |dw:1359337550325:dw|

    • one year ago
  4. Azteck
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    I haven't thoroughly studied physics yet. I think this is better off in the physics section. But I think you're meant to convert the mass into kg's first before doing anything else. And the kilojoules to joules.

    • one year ago
  5. sat_chen
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    this if from my chemistry book all its asking to do is conversion

    • one year ago
  6. sat_chen
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    the formula is given just have to apply it and i have no clue

    • one year ago
  7. Azteck
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    1.554 × 103 kJ ? Is it 1.554 x 10^3 kJ.

    • one year ago
  8. sat_chen
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    yes

    • one year ago
  9. Azteck
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    Okay.

    • one year ago
  10. sat_chen
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    i converted it to J thats why its 1.554*10^6 in my attempt

    • one year ago
  11. Azteck
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    SO it's this? \[1.554\times 10^6 \times \frac{ kgm^x }{ s^x }\]

    • one year ago
  12. sat_chen
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    ill post a print screen of the problem

    • one year ago
  13. sat_chen
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    • one year ago
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  14. sat_chen
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    sorry i should have probably posted the problem earlier

    • one year ago
  15. Azteck
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    Okay, Do you have the correct answer? Like an answer sheet or something?

    • one year ago
  16. sat_chen
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    no i cant get the solution it would be 0 points after that :)

    • one year ago
  17. sat_chen
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    i can try random answer to see if it gives me hint

    • one year ago
  18. sat_chen
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    i have 5 attempts to get it right

    • one year ago
  19. Azteck
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    I got some weird number. I got \[4.564\times 10^{13}\]

    • one year ago
  20. Azteck
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    That's to 4 significant numbers

    • one year ago
  21. sat_chen
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    ok im gonna try that see if its right

    • one year ago
  22. sat_chen
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    nope

    • one year ago
  23. Azteck
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    No it's not.

    • one year ago
  24. sat_chen
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    not the right answer

    • one year ago
  25. Azteck
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    Don't you have to find the mass of the water?

    • one year ago
  26. sat_chen
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    no we dont

    • one year ago
  27. sat_chen
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    we are just trying to do some conversion this is Chapter 2 should be some basic stuff

    • one year ago
  28. Azteck
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    Wait mate. You're trying to find the change in mass?

    • one year ago
  29. sat_chen
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    yes

    • one year ago
  30. sat_chen
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    the question does say that :P

    • one year ago
  31. Azteck
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    Man, heat of combustion keeps popping up in my head for some reason.

    • one year ago
  32. sat_chen
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    so would you do something like mole so 12.096/1.008 and 96/16 and get the value in mole form

    • one year ago
  33. Azteck
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    I'm not sure but it's worth a try. because heat of combustion is sort of what this experiment sort of is. Because you got your energy/heat released and then you got your mass changes and stuff.

    • one year ago
  34. sat_chen
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    yea its nothing complicated like that i have just started to dip into basic chemisty

    • one year ago
  35. Azteck
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    What year/grade is this?

    • one year ago
  36. sat_chen
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    first year chemisty college not incredibly basic but 101

    • one year ago
  37. sat_chen
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    so far we have just learned how to name basic stuff, learning to name polyatomic ions etc emperical formula stuff like that really easy stuff i aced all the other problem but this one is tripping me up

    • one year ago
  38. Mertsj
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    Just plug into the equation E = mc^3. The energy is given, you know the speed of light. Calculate mass

    • one year ago
  39. Azteck
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    Okay. I don't think I can help. I still have one year until universtiy/college. I'm afraid I can't help you.

    • one year ago
  40. Azteck
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    @Mertsj got you covered.

    • one year ago
  41. sat_chen
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    so would you |dw:1359339344388:dw|

    • one year ago
  42. sat_chen
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    and square the speed of light

    • one year ago
  43. sat_chen
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    then change from g to kg by dividing by 1000 or would you conver to mole

    • one year ago
  44. Azteck
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    ANd then I think you might subtract what you get from the mass of the oxygen and hydrogen molecules...

    • one year ago
  45. sat_chen
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    so heres what im doing right now since m = e/c^2

    • one year ago
  46. sat_chen
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    first i change the 10.965/1.001 and 87/16 to convert it to mole

    • one year ago
  47. sat_chen
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    then i divide 1554000/2.9*10^8

    • one year ago
  48. Mertsj
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    E should be in joules, m in kilograms and c in meters per second

    • one year ago
  49. snapcracklepopz
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    sorry to interrupt but can someone help me after you are done helping this person with their question please?

    • one year ago
  50. sat_chen
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    i really am not getting this

    • one year ago
  51. Mertsj
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    \[\frac{1.554\times 10^6}{(3\times 10^8)^2}=.1727 \times 10^{-10} kg\]

    • one year ago
  52. sat_chen
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    yea ive done that before is that just it?

    • one year ago
  53. sat_chen
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    then you convert from kg to g?

    • one year ago
  54. Mertsj
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    Multiply by 1000

    • one year ago
  55. Mertsj
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    That's what I think it is. Because the equation tells you how much mass is needed to produce that much energy.

    • one year ago
  56. sat_chen
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    nope thats not it

    • one year ago
  57. sat_chen
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    oops i messed up

    • one year ago
  58. sat_chen
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    hold on i forgot to square

    • one year ago
  59. Mertsj
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    \[.1727 \times 10^{-10}kg=.1727 \times 10^{-7}g = 1.727 \times 10^{-8}g\]

    • one year ago
  60. sat_chen
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    yea but i ran out of turns and that was the answe r:(

    • one year ago
  61. sat_chen
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    well thanks a lot for your help

    • one year ago
  62. Mertsj
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    What was the answer?

    • one year ago
  63. sat_chen
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    1.72*10^-8

    • one year ago
  64. Mertsj
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    yep. I thought so.

    • one year ago
  65. sat_chen
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    yea im gonna have to hit the books again and learn why i didnt get it thanks a lot

    • one year ago
  66. Mertsj
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    yw

    • one year ago
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