anonymous
  • anonymous
The bar representing which of the following probabilities on a histogram would be the highest? A.1/30 B.1/15 C.1/10 D.2/15 help asap !! please
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
convert each fraction to a decimal number and that will allow you to compare the numbers easier
jim_thompson5910
  • jim_thompson5910
for example 1/30 = 0.0333333... 1/15 = 0.0666667 So we can see that 1/15 is larger than 1/30 since 0.0666667 is larger than 0.033333
anonymous
  • anonymous
so it would be b?

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More answers

jim_thompson5910
  • jim_thompson5910
if you just had those two fractions, yes but you need to compare the rest of the fractions
anonymous
  • anonymous
c is 0.1 and d is 0.13 so than it would be d than?
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
oh okay thank you,
jim_thompson5910
  • jim_thompson5910
you're welcome
anonymous
  • anonymous
Do you know anything about this?
jim_thompson5910
  • jim_thompson5910
that's the combination of choosing 7 things out of 9 basically it's asking "how many ways are there to choose 7 items out of 9 where order does not matter"
anonymous
  • anonymous
I don't understand, cause the choices are A.66 B.55 C.36 D.45
jim_thompson5910
  • jim_thompson5910
have you learned about permutations?
anonymous
  • anonymous
no , this is online math,
jim_thompson5910
  • jim_thompson5910
I figured that, but I would have also figured that you have learned about permutations or combinations by now
jim_thompson5910
  • jim_thompson5910
seems odd how they skipped over that
anonymous
  • anonymous
No, it was never on any of the information given to me for each section,
jim_thompson5910
  • jim_thompson5910
well luckily we can take advantage of the fact that 9 C 7 = 9 C 2 9 C 2 = (9*8)/2 = ???
anonymous
  • anonymous
36
jim_thompson5910
  • jim_thompson5910
so 9 C 7 = 36 as well
jim_thompson5910
  • jim_thompson5910
you can also use Pascals triangle to get the same thing
anonymous
  • anonymous
what about this? If a probability distribution is 5/12,1/6 ,1/4 , x, what is the value of x? A.1/3 B.1/6 C.1/12 D.1/4
jim_thompson5910
  • jim_thompson5910
add up all the fractions including x and set it equal to 1 then solve for x
jim_thompson5910
  • jim_thompson5910
5/12 + 1/6 + 1/4 + x = 1 solve this for x
anonymous
  • anonymous
i don't know, 7/22?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
oh wait, one sec
anonymous
  • anonymous
i don't undersad
anonymous
  • anonymous
understand*
jim_thompson5910
  • jim_thompson5910
what do you get when you combine these fractions 5/12 + 1/6 + 1/4
anonymous
  • anonymous
i don't know , cause they have different numbers do i need them both to get 12?
jim_thompson5910
  • jim_thompson5910
yes you need all the denominators to be equal to 12
anonymous
  • anonymous
12/12?
anonymous
  • anonymous
you multiply 6 with 2 and 4 with 3 ,
jim_thompson5910
  • jim_thompson5910
5/12 = 5/12 1/6 = 2/12 1/4 = 3/12 ----------------- 5/12 + 1/6 + 1/4 is the same as 5/12 + 2/12 + 3/12
anonymous
  • anonymous
10/12 reduced to 5/6?
jim_thompson5910
  • jim_thompson5910
good
anonymous
  • anonymous
thaat not right
jim_thompson5910
  • jim_thompson5910
we're not done yet
anonymous
  • anonymous
oh
jim_thompson5910
  • jim_thompson5910
but we're on the right path to getting there
anonymous
  • anonymous
okay whats next?
jim_thompson5910
  • jim_thompson5910
5/12 + 1/6 + 1/4 + x = 1 is the same as 5/6 + x = 1 Now subtract 5/6 from both sides to isolate x 5/6 + x - 5/6 = 1 - 5/6 x = 1 - 5/6 x = ???
anonymous
  • anonymous
4/6 reduced to 2/3? but that not on there either?
anonymous
  • anonymous
nevermind 0.16666666666
jim_thompson5910
  • jim_thompson5910
no not this |dw:1359342264313:dw| but this |dw:1359342279294:dw|
anonymous
  • anonymous
so it be 1/5?
anonymous
  • anonymous
1/6*
jim_thompson5910
  • jim_thompson5910
1/6 yep
anonymous
  • anonymous
Is it okay if i just message you and you help me please?
jim_thompson5910
  • jim_thompson5910
sure, but I don't want to do every problem for you just letting you know

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