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Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{\sqrt{x}1}=\frac{\sqrt{x}1\sqrt{x}}{\sqrt{x}1}\]

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1So we see that the left side and the right side are identical so the equation is true of all values of x that are greater than or equal to 0

qwerter
 2 years ago
Best ResponseYou've already chosen the best response.0why did you add a negative sqrtx to the left? and I am trying to solve for x, not prove that it is true.

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1I wanted the denominator on the left to be the same as the denominator on the right so I multiplied numerator and denominator by 1

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1And I did solve for x. x is all real numbers greater than or equal to 0. Just because there are many solutions does not mean the problem is not solved.

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1It's sort of like if you have to solve an equation such as: x+3 = x+3 That is true for all real numbers.

qwerter
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, I guess I was thinking that I had to isolate x and get an actual value. But thank you!!

qwerter
 2 years ago
Best ResponseYou've already chosen the best response.0wait, on the right, where did the extra sqrtx come from?

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.1Had to rewrite the number 1 as: \[\frac{\sqrt{x}1}{\sqrt{x}1}\]

qwerter
 2 years ago
Best ResponseYou've already chosen the best response.0so where did the extra sqrtx come from, though?

qwerter
 2 years ago
Best ResponseYou've already chosen the best response.0ahhh, okay! thanks again!
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