## onedirection 2 years ago please help...THE SUM OF THREE CONSECUTIVE INTERGERS IS 54. FIND THE NUMBERS

1. UnkleRhaukus

the the smallest of the consecutive number be \(n\) this makes the three consecutive integers \(n,n+1,n+2\) so the sum of them will be \[(n)+(n+1)+(n+2)\] and we know the sum is \(54\) so we have \[(n)+(n+1)+(n+2)=54\] simplify this and solve for \(n\)

2. UnkleRhaukus

the the* let the

3. onedirection

THanks you so much! I knew this type of formula would be somewhere lettme figure it out and i'll get back to you

4. UnkleRhaukus

sure

5. onedirection

n+n+1+n+2=54 3n=54-1-2 3n=51 n= 17

6. onedirection

thanks so much!

7. onedirection

54divided by 3 is 18

8. onedirection

so by simply dividing, it wouldn't be the right answer, so u have to get a letter, and then get the formula

9. onedirection

thanks you, I have a math exam, and this really helped

10. UnkleRhaukus

you have found \(n=17\) and we set the consecutive integers to be \(n,n+1,n+2\) substitute \(n\) and you'll have the numbers

11. onedirection

huh? oh i thought i was done...ok

12. onedirection

17+18+19

13. onedirection

I didn't know i had to do that...consecutive means...one after the other not the smallest

14. onedirection

not the same*** not the smallest

15. UnkleRhaukus

yeah consecutive does mean one after the other finally you can check you solution does \(17+18+19=54?\)

16. onedirection

ok thank you