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onedirection

  • one year ago

please help...THE SUM OF THREE CONSECUTIVE INTERGERS IS 54. FIND THE NUMBERS

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  1. UnkleRhaukus
    • one year ago
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    the the smallest of the consecutive number be \(n\) this makes the three consecutive integers \(n,n+1,n+2\) so the sum of them will be \[(n)+(n+1)+(n+2)\] and we know the sum is \(54\) so we have \[(n)+(n+1)+(n+2)=54\] simplify this and solve for \(n\)

  2. UnkleRhaukus
    • one year ago
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    the the* let the

  3. onedirection
    • one year ago
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    THanks you so much! I knew this type of formula would be somewhere lettme figure it out and i'll get back to you

  4. UnkleRhaukus
    • one year ago
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    sure

  5. onedirection
    • one year ago
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    n+n+1+n+2=54 3n=54-1-2 3n=51 n= 17

  6. onedirection
    • one year ago
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    thanks so much!

  7. onedirection
    • one year ago
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    54divided by 3 is 18

  8. onedirection
    • one year ago
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    so by simply dividing, it wouldn't be the right answer, so u have to get a letter, and then get the formula

  9. onedirection
    • one year ago
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    thanks you, I have a math exam, and this really helped

  10. UnkleRhaukus
    • one year ago
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    you have found \(n=17\) and we set the consecutive integers to be \(n,n+1,n+2\) substitute \(n\) and you'll have the numbers

  11. onedirection
    • one year ago
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    huh? oh i thought i was done...ok

  12. onedirection
    • one year ago
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    17+18+19

  13. onedirection
    • one year ago
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    I didn't know i had to do that...consecutive means...one after the other not the smallest

  14. onedirection
    • one year ago
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    not the same*** not the smallest

  15. UnkleRhaukus
    • one year ago
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    yeah consecutive does mean one after the other finally you can check you solution does \(17+18+19=54?\)

  16. onedirection
    • one year ago
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    ok thank you

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