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- anonymous

please help...THE SUM OF THREE CONSECUTIVE INTERGERS IS 54. FIND THE NUMBERS

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- anonymous

please help...THE SUM OF THREE CONSECUTIVE INTERGERS IS 54. FIND THE NUMBERS

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- UnkleRhaukus

the the smallest of the consecutive number be \(n\)
this makes the three consecutive integers \(n,n+1,n+2\)
so the sum of them will be
\[(n)+(n+1)+(n+2)\]
and we know the sum is \(54\)
so we have \[(n)+(n+1)+(n+2)=54\]
simplify this and solve for \(n\)

- UnkleRhaukus

the the* let the

- anonymous

THanks you so much! I knew this type of formula would be somewhere
lettme figure it out and i'll get back to you

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- UnkleRhaukus

sure

- anonymous

n+n+1+n+2=54
3n=54-1-2
3n=51
n= 17

- anonymous

thanks so much!

- anonymous

54divided by 3 is 18

- anonymous

so by simply dividing, it wouldn't be the right answer, so u have to get a letter, and then get the formula

- anonymous

thanks you, I have a math exam, and this really helped

- UnkleRhaukus

you have found \(n=17\)
and we set the consecutive integers to be \(n,n+1,n+2\)
substitute \(n\) and you'll have the numbers

- anonymous

huh?
oh i thought i was done...ok

- anonymous

17+18+19

- anonymous

I didn't know i had to do that...consecutive means...one after the other not the smallest

- anonymous

not the same*** not the smallest

- UnkleRhaukus

yeah consecutive does mean one after the other
finally you can check you solution
does \(17+18+19=54?\)

- anonymous

ok thank you

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