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please help...THE SUM OF THREE CONSECUTIVE INTERGERS IS 54. FIND THE NUMBERS
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UnkleRhaukus
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the the smallest of the consecutive number be \(n\)
this makes the three consecutive integers \(n,n+1,n+2\)
so the sum of them will be
\[(n)+(n+1)+(n+2)\]
and we know the sum is \(54\)
so we have \[(n)+(n+1)+(n+2)=54\]
simplify this and solve for \(n\)
UnkleRhaukus
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the the* let the
onedirection
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THanks you so much! I knew this type of formula would be somewhere
lettme figure it out and i'll get back to you
UnkleRhaukus
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sure
onedirection
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n+n+1+n+2=54
3n=54-1-2
3n=51
n= 17
onedirection
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thanks so much!
onedirection
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54divided by 3 is 18
onedirection
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so by simply dividing, it wouldn't be the right answer, so u have to get a letter, and then get the formula
onedirection
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thanks you, I have a math exam, and this really helped
UnkleRhaukus
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you have found \(n=17\)
and we set the consecutive integers to be \(n,n+1,n+2\)
substitute \(n\) and you'll have the numbers
onedirection
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huh?
oh i thought i was done...ok
onedirection
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17+18+19
onedirection
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I didn't know i had to do that...consecutive means...one after the other not the smallest
onedirection
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not the same*** not the smallest
UnkleRhaukus
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yeah consecutive does mean one after the other
finally you can check you solution
does \(17+18+19=54?\)
onedirection
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ok thank you