how do you graph the slope 5/4 using rise over run?

- anonymous

how do you graph the slope 5/4 using rise over run?

- chestercat

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- jim_thompson5910

start at any point that is on the line
then go up 5 units, then go 4 units to the right to get to the next point

- anonymous

can you start at the origin?

- jim_thompson5910

say we have this starting point
|dw:1359348640310:dw|

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## More answers

- jim_thompson5910

if you go up 5 units you land here
|dw:1359348680876:dw|

- jim_thompson5910

if you go 4 units to the right, you will land here
|dw:1359348711180:dw|

- jim_thompson5910

|dw:1359348750015:dw|

- jim_thompson5910

then you would draw a line through those two points
|dw:1359348773195:dw|

- jim_thompson5910

now you can move that "starting point" to wherever you want

- anonymous

i still don't understand about who to find the starting point

- anonymous

You need a Y- intercept

- anonymous

the question might give you it

- anonymous

the y-int 5/4 also

- anonymous

|dw:1359350257526:dw|

- anonymous

are you sure? well if you dont have you you can start anywhere from the graph...the graph i drew is negative slope tho

- anonymous

yeah that last graph probably confused them lol ; D

- anonymous

Can you write out the entire question as its seen?

- anonymous

@kaisan

- anonymous

which graphj

- anonymous

ok its y=5/4x-5/4

- anonymous

the one with the negative slope

- anonymous

ok if you draw the graph the y-intercept with be 5/4 or 1 1/4

- anonymous

|dw:1359350723423:dw|

- anonymous

then the slope is 5/4 rise over run: so you rise 5 and you run 4

- anonymous

|dw:1359350933733:dw|

- anonymous

so its best to start with the y-intercept?

- anonymous

yes that's what I always do. I plug the y-intercept in first and then you do the slope to find the next point so you can draw the line = )

- anonymous

so if the y-int was -5/4 i would go 5 units first then to the right 4 units? but i still don't understand to start when i'm graphing, i tried starting on the origin but my online hw says its wrong

- anonymous

@bettyboop8904

- anonymous

what do you mean starting on the origin? you should only be putting the y-intercept in. In the graph you have x and y values. With the y-intercept being 5/4 the point is written as
\[(0,\frac{ 5 }{ 4 })\]

- anonymous

If you were to start at the origin the starting equation would have to read
y=(5/4)x+0
or
y=(5/4)x

- anonymous

@kaisan

- anonymous

oh, ok thanks

- anonymous

but if your slope was -(5/4) then the equation would read
\[y=-\frac{ 5 }{ 4 }x +\frac{ 5 }{ 4 }\]
then you would fall down 5 and then go to the right 4 or you could rise 5 and then go to the left 4; Just as long as when you do the rise over run you are only using one negative motion (fall down or go left bc those are negative x- and y-values) for only one of the numbers. You can place the negative either on the top or on the bottom but never both. @kaisan

- anonymous

|dw:1359353149250:dw|

- anonymous

this shows both ways on the graph

- anonymous

thx

- anonymous

your welcome = )

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