kaisan
how do you graph the slope 5/4 using rise over run?
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jim_thompson5910
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start at any point that is on the line
then go up 5 units, then go 4 units to the right to get to the next point
kaisan
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can you start at the origin?
jim_thompson5910
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say we have this starting point
|dw:1359348640310:dw|
jim_thompson5910
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if you go up 5 units you land here
|dw:1359348680876:dw|
jim_thompson5910
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if you go 4 units to the right, you will land here
|dw:1359348711180:dw|
jim_thompson5910
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|dw:1359348750015:dw|
jim_thompson5910
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then you would draw a line through those two points
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jim_thompson5910
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now you can move that "starting point" to wherever you want
kaisan
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i still don't understand about who to find the starting point
julianahe
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You need a Y- intercept
julianahe
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the question might give you it
kaisan
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the y-int 5/4 also
julianahe
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|dw:1359350257526:dw|
julianahe
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are you sure? well if you dont have you you can start anywhere from the graph...the graph i drew is negative slope tho
bettyboop8904
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yeah that last graph probably confused them lol ; D
bettyboop8904
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Can you write out the entire question as its seen?
bettyboop8904
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@kaisan
julianahe
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which graphj
kaisan
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ok its y=5/4x-5/4
bettyboop8904
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the one with the negative slope
bettyboop8904
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ok if you draw the graph the y-intercept with be 5/4 or 1 1/4
bettyboop8904
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|dw:1359350723423:dw|
bettyboop8904
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then the slope is 5/4 rise over run: so you rise 5 and you run 4
bettyboop8904
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|dw:1359350933733:dw|
kaisan
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so its best to start with the y-intercept?
bettyboop8904
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yes that's what I always do. I plug the y-intercept in first and then you do the slope to find the next point so you can draw the line = )
kaisan
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so if the y-int was -5/4 i would go 5 units first then to the right 4 units? but i still don't understand to start when i'm graphing, i tried starting on the origin but my online hw says its wrong
kaisan
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@bettyboop8904
bettyboop8904
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what do you mean starting on the origin? you should only be putting the y-intercept in. In the graph you have x and y values. With the y-intercept being 5/4 the point is written as
\[(0,\frac{ 5 }{ 4 })\]
bettyboop8904
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If you were to start at the origin the starting equation would have to read
y=(5/4)x+0
or
y=(5/4)x
bettyboop8904
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@kaisan
kaisan
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oh, ok thanks
bettyboop8904
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but if your slope was -(5/4) then the equation would read
\[y=-\frac{ 5 }{ 4 }x +\frac{ 5 }{ 4 }\]
then you would fall down 5 and then go to the right 4 or you could rise 5 and then go to the left 4; Just as long as when you do the rise over run you are only using one negative motion (fall down or go left bc those are negative x- and y-values) for only one of the numbers. You can place the negative either on the top or on the bottom but never both. @kaisan
bettyboop8904
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|dw:1359353149250:dw|
bettyboop8904
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this shows both ways on the graph
kaisan
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thx
bettyboop8904
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your welcome = )