anonymous
  • anonymous
how do you graph the slope 5/4 using rise over run?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jim_thompson5910
  • jim_thompson5910
start at any point that is on the line then go up 5 units, then go 4 units to the right to get to the next point
anonymous
  • anonymous
can you start at the origin?
jim_thompson5910
  • jim_thompson5910
say we have this starting point |dw:1359348640310:dw|

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jim_thompson5910
  • jim_thompson5910
if you go up 5 units you land here |dw:1359348680876:dw|
jim_thompson5910
  • jim_thompson5910
if you go 4 units to the right, you will land here |dw:1359348711180:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1359348750015:dw|
jim_thompson5910
  • jim_thompson5910
then you would draw a line through those two points |dw:1359348773195:dw|
jim_thompson5910
  • jim_thompson5910
now you can move that "starting point" to wherever you want
anonymous
  • anonymous
i still don't understand about who to find the starting point
anonymous
  • anonymous
You need a Y- intercept
anonymous
  • anonymous
the question might give you it
anonymous
  • anonymous
the y-int 5/4 also
anonymous
  • anonymous
|dw:1359350257526:dw|
anonymous
  • anonymous
are you sure? well if you dont have you you can start anywhere from the graph...the graph i drew is negative slope tho
anonymous
  • anonymous
yeah that last graph probably confused them lol ; D
anonymous
  • anonymous
Can you write out the entire question as its seen?
anonymous
  • anonymous
@kaisan
anonymous
  • anonymous
which graphj
anonymous
  • anonymous
ok its y=5/4x-5/4
anonymous
  • anonymous
the one with the negative slope
anonymous
  • anonymous
ok if you draw the graph the y-intercept with be 5/4 or 1 1/4
anonymous
  • anonymous
|dw:1359350723423:dw|
anonymous
  • anonymous
then the slope is 5/4 rise over run: so you rise 5 and you run 4
anonymous
  • anonymous
|dw:1359350933733:dw|
anonymous
  • anonymous
so its best to start with the y-intercept?
anonymous
  • anonymous
yes that's what I always do. I plug the y-intercept in first and then you do the slope to find the next point so you can draw the line = )
anonymous
  • anonymous
so if the y-int was -5/4 i would go 5 units first then to the right 4 units? but i still don't understand to start when i'm graphing, i tried starting on the origin but my online hw says its wrong
anonymous
  • anonymous
@bettyboop8904
anonymous
  • anonymous
what do you mean starting on the origin? you should only be putting the y-intercept in. In the graph you have x and y values. With the y-intercept being 5/4 the point is written as \[(0,\frac{ 5 }{ 4 })\]
anonymous
  • anonymous
If you were to start at the origin the starting equation would have to read y=(5/4)x+0 or y=(5/4)x
anonymous
  • anonymous
@kaisan
anonymous
  • anonymous
oh, ok thanks
anonymous
  • anonymous
but if your slope was -(5/4) then the equation would read \[y=-\frac{ 5 }{ 4 }x +\frac{ 5 }{ 4 }\] then you would fall down 5 and then go to the right 4 or you could rise 5 and then go to the left 4; Just as long as when you do the rise over run you are only using one negative motion (fall down or go left bc those are negative x- and y-values) for only one of the numbers. You can place the negative either on the top or on the bottom but never both. @kaisan
anonymous
  • anonymous
|dw:1359353149250:dw|
anonymous
  • anonymous
this shows both ways on the graph
anonymous
  • anonymous
thx
anonymous
  • anonymous
your welcome = )

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