## anonymous 3 years ago how do you graph the slope 5/4 using rise over run?

1. jim_thompson5910

start at any point that is on the line then go up 5 units, then go 4 units to the right to get to the next point

2. anonymous

can you start at the origin?

3. jim_thompson5910

say we have this starting point |dw:1359348640310:dw|

4. jim_thompson5910

if you go up 5 units you land here |dw:1359348680876:dw|

5. jim_thompson5910

if you go 4 units to the right, you will land here |dw:1359348711180:dw|

6. jim_thompson5910

|dw:1359348750015:dw|

7. jim_thompson5910

then you would draw a line through those two points |dw:1359348773195:dw|

8. jim_thompson5910

now you can move that "starting point" to wherever you want

9. anonymous

i still don't understand about who to find the starting point

10. anonymous

You need a Y- intercept

11. anonymous

the question might give you it

12. anonymous

the y-int 5/4 also

13. anonymous

|dw:1359350257526:dw|

14. anonymous

are you sure? well if you dont have you you can start anywhere from the graph...the graph i drew is negative slope tho

15. anonymous

yeah that last graph probably confused them lol ; D

16. anonymous

Can you write out the entire question as its seen?

17. anonymous

@kaisan

18. anonymous

which graphj

19. anonymous

ok its y=5/4x-5/4

20. anonymous

the one with the negative slope

21. anonymous

ok if you draw the graph the y-intercept with be 5/4 or 1 1/4

22. anonymous

|dw:1359350723423:dw|

23. anonymous

then the slope is 5/4 rise over run: so you rise 5 and you run 4

24. anonymous

|dw:1359350933733:dw|

25. anonymous

26. anonymous

yes that's what I always do. I plug the y-intercept in first and then you do the slope to find the next point so you can draw the line = )

27. anonymous

so if the y-int was -5/4 i would go 5 units first then to the right 4 units? but i still don't understand to start when i'm graphing, i tried starting on the origin but my online hw says its wrong

28. anonymous

@bettyboop8904

29. anonymous

what do you mean starting on the origin? you should only be putting the y-intercept in. In the graph you have x and y values. With the y-intercept being 5/4 the point is written as $(0,\frac{ 5 }{ 4 })$

30. anonymous

If you were to start at the origin the starting equation would have to read y=(5/4)x+0 or y=(5/4)x

31. anonymous

@kaisan

32. anonymous

oh, ok thanks

33. anonymous

but if your slope was -(5/4) then the equation would read $y=-\frac{ 5 }{ 4 }x +\frac{ 5 }{ 4 }$ then you would fall down 5 and then go to the right 4 or you could rise 5 and then go to the left 4; Just as long as when you do the rise over run you are only using one negative motion (fall down or go left bc those are negative x- and y-values) for only one of the numbers. You can place the negative either on the top or on the bottom but never both. @kaisan

34. anonymous

|dw:1359353149250:dw|

35. anonymous

this shows both ways on the graph

36. anonymous

thx

37. anonymous