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geerky42

  • 2 years ago

\[\Large \int\limits_{1}^{2}(x-1)\sqrt{2-x}\space dx\]

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  1. dumbcow
    • 2 years ago
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    im thinking integration by parts ... have you tried that?

  2. geerky42
    • 2 years ago
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    wELL, i'M NEW TO INTEGRAL, i KNOW SOME TECHNIQUES BUT NOT COMPETELY CONFIDENT WITH IT. i'M CURRENTLY WORK WITH u-sUBSTITUTION. Sorry about caps.

  3. geerky42
    • 2 years ago
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    I don't see how I can use u-substitution for this problem...

  4. dumbcow
    • 2 years ago
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    oh ok ... yeah substitution may work but i don't see it right away integration by parts is a technique when you have a product of 2 distinct functions \[\int\limits_{?}^{?} f(x) *g(x) dx\]

  5. dumbcow
    • 2 years ago
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    the equation is given as: \[\int\limits_{?}^{?} u*dv = uv -\int\limits_{?}^{?}v*du\] where u is f(x) and dv is g(x)

  6. geerky42
    • 2 years ago
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    Ok, I'm giving it a try.

  7. geerky42
    • 2 years ago
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    I don't think it will work. While I'm attempting to solve it, it's getting uglier.

  8. dumbcow
    • 2 years ago
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    no it will work but yes it can get uglier in the process ... anyway it takes some getting used to i found how u-substitution will work \[u = 2-x\] \[du = -dx\] \[\rightarrow -\int\limits_{?}^{?}(1-u) \sqrt{u} du = -\int\limits_{?}^{?} \sqrt{u} - u \sqrt{u}\]

  9. geerky42
    • 2 years ago
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    Hmm clever! Thanks.

  10. dumbcow
    • 2 years ago
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    yw

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