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 one year ago
PLZ HELP#VERYCONFUSED rewrite each expression in term with no power greater than 1
 one year ago
PLZ HELP#VERYCONFUSED rewrite each expression in term with no power greater than 1

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0it is simply \[\cos(\theta)\cos(\theta)\cos(\theta)\]

drasy22
 one year ago
Best ResponseYou've already chosen the best response.0no i have to use like identities

drasy22
 one year ago
Best ResponseYou've already chosen the best response.0ex if it is sin ^4 u do sin2)^2 and then you put the identitiy for sin^2 and then solve

drasy22
 one year ago
Best ResponseYou've already chosen the best response.0but i have no idea how to do this

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hmm I'm not familiar with any identities that decrease the power on trig functions. Are you sure it wasn't suppose to be \(cos (3\theta)\) ?

drasy22
 one year ago
Best ResponseYou've already chosen the best response.0yes i am sure but thanks

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well start with \[\cos(\theta) (\cos^2(\theta)) = \cos(\theta)(1  \sin^2(\theta))\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Oh I guess we could use the HalfAngle Formulas to decrease power. I somehow forgot about those when I made my last comment :) lol

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Here's a helpful identity we can use. \[\large \color{royalblue}{\cos^2x=\frac{1+\cos2x}{2}}\]

drasy22
 one year ago
Best ResponseYou've already chosen the best response.0yeah u are right i will have to use the power reducing identities

drasy22
 one year ago
Best ResponseYou've already chosen the best response.0yeah i started by using that but i don't know what to do after that step

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \cos^3x\quad =\quad \cos x \color{royalblue}{\cos^2 x} \quad = \quad \cos x \color{royalblue}{\frac{1+\cos2x}{2}}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Im not sure if that's exactly what you're looking for. But something to notice here is that we no longer even have a squared cosine, since the two cosines we're left with have different INSIDES, we can't combine them that way.

drasy22
 one year ago
Best ResponseYou've already chosen the best response.0yes i am looking for this but i think it is OK i will ask my teacher. but thanks both of u for ur help!!!
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