anonymous
  • anonymous
PLZ HELP#VERYCONFUSED rewrite each expression in term with no power greater than 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\cos ^{3}\]
anonymous
  • anonymous
cos^3theta
anonymous
  • anonymous
\[\cos ^{3}\theta \]

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campbell_st
  • campbell_st
it is simply \[\cos(\theta)\cos(\theta)\cos(\theta)\]
anonymous
  • anonymous
no i have to use like identities
anonymous
  • anonymous
ex if it is sin ^4 u do sin2)^2 and then you put the identitiy for sin^2 and then solve
anonymous
  • anonymous
but i have no idea how to do this
anonymous
  • anonymous
@zepdrix
zepdrix
  • zepdrix
Hmm I'm not familiar with any identities that decrease the power on trig functions. Are you sure it wasn't suppose to be \(cos (3\theta)\) ?
anonymous
  • anonymous
yes i am sure but thanks
campbell_st
  • campbell_st
well start with \[\cos(\theta) (\cos^2(\theta)) = \cos(\theta)(1 - \sin^2(\theta))\]
anonymous
  • anonymous
hmmm k
zepdrix
  • zepdrix
Oh I guess we could use the Half-Angle Formulas to decrease power. I somehow forgot about those when I made my last comment :) lol
zepdrix
  • zepdrix
Here's a helpful identity we can use. \[\large \color{royalblue}{\cos^2x=\frac{1+\cos2x}{2}}\]
anonymous
  • anonymous
yeah u are right i will have to use the power reducing identities
anonymous
  • anonymous
yeah i started by using that but i don't know what to do after that step
zepdrix
  • zepdrix
\[\large \cos^3x\quad =\quad \cos x \color{royalblue}{\cos^2 x} \quad = \quad \cos x \color{royalblue}{\frac{1+\cos2x}{2}}\]
zepdrix
  • zepdrix
Im not sure if that's exactly what you're looking for. But something to notice here is that we no longer even have a squared cosine, since the two cosines we're left with have different INSIDES, we can't combine them that way.
anonymous
  • anonymous
yes i am looking for this but i think it is OK i will ask my teacher. but thanks both of u for ur help!!!

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