Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Hey guys im trying to convert non linear eqn into linear, where can I find more information about this?

Differential Equations
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

It depends on the type of equation. There are lots of different ways to do it.
yes, i'm just trying to refresh my knowledge on it. Do you know of any good source where I can see some examples?
For Differential Equations after calculus or for derivatives?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

well I guess it would be after calculus but this is the eqn \[dy/dt=-5y^2+3uy+6u^2\]
There is no way to make that linear. It's a quadratic and polynomials of degrees other than one cannot be changed to become linear.
yikes well too bad I have it as an assignment question :P thanks though
Also, are you sure all the variables are right? Because right now you have a diff.eq in which you're deriving with respect to a variable that isn't on the right side of your equation...
dy/dt? there are ys on the right side?
Yes but the equation is taking the derivative with respect to t. It would be the same as if I had equation y = x^2 + xy + y^2 and then took the derivative with respect to t I would get dy/dt = 0 because I have no variables with t in them, therefore everything else is considered a constant. Since you don't have t on the right side anymore, I'm assuming that the original equation was something like (−5y^2+3uy+6u^2)*t Otherwise, the right side would be dy/du
good catch but the question given has dy/dt though, i'm guessing prof made a mistake :)
sorry just realized both u and y are a function of t, should be y(t) and u(t)

Not the answer you are looking for?

Search for more explanations.

Ask your own question