In lect1-Differentiation..while ascertaing the coordinates for Q point x0 and Δx were used for X coordinates but y did he used f(x0+Δx) for Y coordinates inspite of using y0and Δy??
OCW Scholar - Single Variable Calculus
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Δx isn't a literal position, but rather, it's the distance Q is from x0 along the x-axis. This is why Δx, "delta x", is also known as the "change in x".
So we know P is at (x0, f(x0)), where f(x0) is also known as y0.
The point Q's x-coordinate is Δx distance away from x0, so its x-coordinate is x0+Δx.
The point Q is actually at (x0+Δx, f(x0+Δx)).
Δy, similarly isn't the y-coordinate of Q, but rather Δy is the distance Q is from P along the y-axis. Δy is "delta y" or the "change in y".
Aside from (x0+Δx, f(x0+Δx)) we can also say Q is at (x0+Δx, y0+Δy).