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Kuoministers
 3 years ago
Help me on this question please... I really dont know where to start thanks!!
Kuoministers
 3 years ago
Help me on this question please... I really dont know where to start thanks!!

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Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge3^{x} + 5 \times 3^{x} = 54\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0to start, we need to isolate the variables, we start by dividing both sides by 3^x, then subtract 5 from both sides, and then multiply both sides by 3^x \[3^x + 5 \times 3^x \div 3^x = 54 \div 3^x\] \[3^x + 5  5 = 54/3^x\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[3^x \times 3^x = 54/3^x \times 3^x  5\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[9^x^2 = 51\] so now we find the square root of each side

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{9^x^2} = \sqrt{51}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the square and square root cancel each other out, so it would be \[9^x \approx 7 \]

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0im not sure but thats not the answer that is in the back of the book :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0divide both sides by 9 \[9^x \div 9 = 7 \div 9\] \[^x = 7/9\]

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0thats not the answer in the book :P

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0i think the way he started the question was wrong cause i was told to keep the same base

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yea, 3^x X 3^x can be written as 3^2x

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0yea i agree on that

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge3^{2x} + 5 = 3^{3} \times 2\] this might help?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How did you get that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359366605554:dw

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0i broke up 54 into 3^3 times 2 cause i wanted to make the base the same which in this case 3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359366719099:dw

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0i didnt see you could factorise 3^x out of that equation!! Thanks so much to both of you :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You can do the 3^x X 3^x = 3^2x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, because its actually 3^x + ( 5 X 3^x )

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You have to either solve inside the bracket first or factorize

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0oh thanks @artix_17 for pointing that out!! I wouldn't have noticed :P
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