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Kuoministers

  • 3 years ago

Help me on this question please... I really dont know where to start thanks!!

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  1. Kuoministers
    • 3 years ago
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    \[\huge3^{x} + 5 \times 3^{x} = 54\]

  2. DeadShot
    • 3 years ago
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    to start, we need to isolate the variables, we start by dividing both sides by 3^x, then subtract 5 from both sides, and then multiply both sides by 3^x \[3^x + 5 \times 3^x \div 3^x = 54 \div 3^x\] \[3^x + 5 - 5 = 54/3^x\]

  3. DeadShot
    • 3 years ago
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    \[3^x \times 3^x = 54/3^x \times 3^x - 5\]

  4. DeadShot
    • 3 years ago
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    \[9^x^2 = 54 -5\]

  5. DeadShot
    • 3 years ago
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    \[9^x^2 = 51\] so now we find the square root of each side

  6. DeadShot
    • 3 years ago
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    \[\sqrt{9^x^2} = \sqrt{51}\]

  7. DeadShot
    • 3 years ago
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    the square and square root cancel each other out, so it would be \[9^x \approx 7 \]

  8. Kuoministers
    • 3 years ago
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    im not sure but thats not the answer that is in the back of the book :P

  9. DeadShot
    • 3 years ago
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    divide both sides by 9 \[9^x \div 9 = 7 \div 9\] \[^x = 7/9\]

  10. Kuoministers
    • 3 years ago
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    @artix_17

  11. Kuoministers
    • 3 years ago
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    thats not the answer in the book :P

  12. artix_17
    • 3 years ago
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    whats your answer?

  13. Kuoministers
    • 3 years ago
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    2

  14. Kuoministers
    • 3 years ago
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    i think the way he started the question was wrong cause i was told to keep the same base

  15. artix_17
    • 3 years ago
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    Yea, 3^x X 3^x can be written as 3^2x

  16. Kuoministers
    • 3 years ago
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    yea i agree on that

  17. Kuoministers
    • 3 years ago
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    \[\huge3^{2x} + 5 = 3^{3} \times 2\] this might help?

  18. artix_17
    • 3 years ago
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    How did you get that?

  19. rizwan_uet
    • 3 years ago
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    |dw:1359366605554:dw|

  20. Kuoministers
    • 3 years ago
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    i broke up 54 into 3^3 times 2 cause i wanted to make the base the same which in this case 3

  21. Kuoministers
    • 3 years ago
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    I GET IT :D

  22. rizwan_uet
    • 3 years ago
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    |dw:1359366719099:dw|

  23. Kuoministers
    • 3 years ago
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    i didnt see you could factorise 3^x out of that equation!! Thanks so much to both of you :)

  24. artix_17
    • 3 years ago
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    You can do the 3^x X 3^x = 3^2x

  25. artix_17
    • 3 years ago
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    can't*

  26. Kuoministers
    • 3 years ago
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    you cant?

  27. artix_17
    • 3 years ago
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    No, because its actually 3^x + ( 5 X 3^x )

  28. artix_17
    • 3 years ago
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    You have to either solve inside the bracket first or factorize

  29. Kuoministers
    • 3 years ago
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    oh thanks @artix_17 for pointing that out!! I wouldn't have noticed :P

  30. artix_17
    • 3 years ago
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    No problem :)

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