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Kuoministers Group Title

Help me on this question please... I really dont know where to start thanks!!

  • one year ago
  • one year ago

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  1. Kuoministers Group Title
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    \[\huge3^{x} + 5 \times 3^{x} = 54\]

    • one year ago
  2. DeadShot Group Title
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    to start, we need to isolate the variables, we start by dividing both sides by 3^x, then subtract 5 from both sides, and then multiply both sides by 3^x \[3^x + 5 \times 3^x \div 3^x = 54 \div 3^x\] \[3^x + 5 - 5 = 54/3^x\]

    • one year ago
  3. DeadShot Group Title
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    \[3^x \times 3^x = 54/3^x \times 3^x - 5\]

    • one year ago
  4. DeadShot Group Title
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    \[9^x^2 = 54 -5\]

    • one year ago
  5. DeadShot Group Title
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    \[9^x^2 = 51\] so now we find the square root of each side

    • one year ago
  6. DeadShot Group Title
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    \[\sqrt{9^x^2} = \sqrt{51}\]

    • one year ago
  7. DeadShot Group Title
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    the square and square root cancel each other out, so it would be \[9^x \approx 7 \]

    • one year ago
  8. Kuoministers Group Title
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    im not sure but thats not the answer that is in the back of the book :P

    • one year ago
  9. DeadShot Group Title
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    divide both sides by 9 \[9^x \div 9 = 7 \div 9\] \[^x = 7/9\]

    • one year ago
  10. Kuoministers Group Title
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    @artix_17

    • one year ago
  11. Kuoministers Group Title
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    thats not the answer in the book :P

    • one year ago
  12. artix_17 Group Title
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    whats your answer?

    • one year ago
  13. Kuoministers Group Title
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    2

    • one year ago
  14. Kuoministers Group Title
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    i think the way he started the question was wrong cause i was told to keep the same base

    • one year ago
  15. artix_17 Group Title
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    Yea, 3^x X 3^x can be written as 3^2x

    • one year ago
  16. Kuoministers Group Title
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    yea i agree on that

    • one year ago
  17. Kuoministers Group Title
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    \[\huge3^{2x} + 5 = 3^{3} \times 2\] this might help?

    • one year ago
  18. artix_17 Group Title
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    How did you get that?

    • one year ago
  19. rizwan_uet Group Title
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    |dw:1359366605554:dw|

    • one year ago
  20. Kuoministers Group Title
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    i broke up 54 into 3^3 times 2 cause i wanted to make the base the same which in this case 3

    • one year ago
  21. Kuoministers Group Title
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    I GET IT :D

    • one year ago
  22. rizwan_uet Group Title
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    |dw:1359366719099:dw|

    • one year ago
  23. Kuoministers Group Title
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    i didnt see you could factorise 3^x out of that equation!! Thanks so much to both of you :)

    • one year ago
  24. artix_17 Group Title
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    You can do the 3^x X 3^x = 3^2x

    • one year ago
  25. artix_17 Group Title
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    can't*

    • one year ago
  26. Kuoministers Group Title
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    you cant?

    • one year ago
  27. artix_17 Group Title
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    No, because its actually 3^x + ( 5 X 3^x )

    • one year ago
  28. artix_17 Group Title
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    You have to either solve inside the bracket first or factorize

    • one year ago
  29. Kuoministers Group Title
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    oh thanks @artix_17 for pointing that out!! I wouldn't have noticed :P

    • one year ago
  30. artix_17 Group Title
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    No problem :)

    • one year ago
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is replying to Can someone tell me what button the professor is hitting...

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