Kuoministers
  • Kuoministers
Help me on this question please... I really dont know where to start thanks!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Kuoministers
  • Kuoministers
\[\huge3^{x} + 5 \times 3^{x} = 54\]
DeadShot
  • DeadShot
to start, we need to isolate the variables, we start by dividing both sides by 3^x, then subtract 5 from both sides, and then multiply both sides by 3^x \[3^x + 5 \times 3^x \div 3^x = 54 \div 3^x\] \[3^x + 5 - 5 = 54/3^x\]
DeadShot
  • DeadShot
\[3^x \times 3^x = 54/3^x \times 3^x - 5\]

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DeadShot
  • DeadShot
\[9^x^2 = 54 -5\]
DeadShot
  • DeadShot
\[9^x^2 = 51\] so now we find the square root of each side
DeadShot
  • DeadShot
\[\sqrt{9^x^2} = \sqrt{51}\]
DeadShot
  • DeadShot
the square and square root cancel each other out, so it would be \[9^x \approx 7 \]
Kuoministers
  • Kuoministers
im not sure but thats not the answer that is in the back of the book :P
DeadShot
  • DeadShot
divide both sides by 9 \[9^x \div 9 = 7 \div 9\] \[^x = 7/9\]
Kuoministers
  • Kuoministers
@artix_17
Kuoministers
  • Kuoministers
thats not the answer in the book :P
anonymous
  • anonymous
whats your answer?
Kuoministers
  • Kuoministers
2
Kuoministers
  • Kuoministers
i think the way he started the question was wrong cause i was told to keep the same base
anonymous
  • anonymous
Yea, 3^x X 3^x can be written as 3^2x
Kuoministers
  • Kuoministers
yea i agree on that
Kuoministers
  • Kuoministers
\[\huge3^{2x} + 5 = 3^{3} \times 2\] this might help?
anonymous
  • anonymous
How did you get that?
anonymous
  • anonymous
|dw:1359366605554:dw|
Kuoministers
  • Kuoministers
i broke up 54 into 3^3 times 2 cause i wanted to make the base the same which in this case 3
Kuoministers
  • Kuoministers
I GET IT :D
anonymous
  • anonymous
|dw:1359366719099:dw|
Kuoministers
  • Kuoministers
i didnt see you could factorise 3^x out of that equation!! Thanks so much to both of you :)
anonymous
  • anonymous
You can do the 3^x X 3^x = 3^2x
anonymous
  • anonymous
can't*
Kuoministers
  • Kuoministers
you cant?
anonymous
  • anonymous
No, because its actually 3^x + ( 5 X 3^x )
anonymous
  • anonymous
You have to either solve inside the bracket first or factorize
Kuoministers
  • Kuoministers
oh thanks @artix_17 for pointing that out!! I wouldn't have noticed :P
anonymous
  • anonymous
No problem :)

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