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Help me on this question please... I really dont know where to start thanks!!

Mathematics
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\[\huge3^{x} + 5 \times 3^{x} = 54\]
to start, we need to isolate the variables, we start by dividing both sides by 3^x, then subtract 5 from both sides, and then multiply both sides by 3^x \[3^x + 5 \times 3^x \div 3^x = 54 \div 3^x\] \[3^x + 5 - 5 = 54/3^x\]
\[3^x \times 3^x = 54/3^x \times 3^x - 5\]

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Other answers:

\[9^x^2 = 54 -5\]
\[9^x^2 = 51\] so now we find the square root of each side
\[\sqrt{9^x^2} = \sqrt{51}\]
the square and square root cancel each other out, so it would be \[9^x \approx 7 \]
im not sure but thats not the answer that is in the back of the book :P
divide both sides by 9 \[9^x \div 9 = 7 \div 9\] \[^x = 7/9\]
thats not the answer in the book :P
whats your answer?
2
i think the way he started the question was wrong cause i was told to keep the same base
Yea, 3^x X 3^x can be written as 3^2x
yea i agree on that
\[\huge3^{2x} + 5 = 3^{3} \times 2\] this might help?
How did you get that?
|dw:1359366605554:dw|
i broke up 54 into 3^3 times 2 cause i wanted to make the base the same which in this case 3
I GET IT :D
|dw:1359366719099:dw|
i didnt see you could factorise 3^x out of that equation!! Thanks so much to both of you :)
You can do the 3^x X 3^x = 3^2x
can't*
you cant?
No, because its actually 3^x + ( 5 X 3^x )
You have to either solve inside the bracket first or factorize
oh thanks @artix_17 for pointing that out!! I wouldn't have noticed :P
No problem :)

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