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Kuoministers
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Help me on this question please... I really dont know where to start thanks!!
 one year ago
 one year ago
Kuoministers Group Title
Help me on this question please... I really dont know where to start thanks!!
 one year ago
 one year ago

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Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
\[\huge3^{x} + 5 \times 3^{x} = 54\]
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
to start, we need to isolate the variables, we start by dividing both sides by 3^x, then subtract 5 from both sides, and then multiply both sides by 3^x \[3^x + 5 \times 3^x \div 3^x = 54 \div 3^x\] \[3^x + 5  5 = 54/3^x\]
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
\[3^x \times 3^x = 54/3^x \times 3^x  5\]
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
\[9^x^2 = 54 5\]
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
\[9^x^2 = 51\] so now we find the square root of each side
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{9^x^2} = \sqrt{51}\]
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
the square and square root cancel each other out, so it would be \[9^x \approx 7 \]
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
im not sure but thats not the answer that is in the back of the book :P
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
divide both sides by 9 \[9^x \div 9 = 7 \div 9\] \[^x = 7/9\]
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
@artix_17
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
thats not the answer in the book :P
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.1
whats your answer?
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
i think the way he started the question was wrong cause i was told to keep the same base
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.1
Yea, 3^x X 3^x can be written as 3^2x
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
yea i agree on that
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
\[\huge3^{2x} + 5 = 3^{3} \times 2\] this might help?
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.1
How did you get that?
 one year ago

rizwan_uet Group TitleBest ResponseYou've already chosen the best response.2
dw:1359366605554:dw
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
i broke up 54 into 3^3 times 2 cause i wanted to make the base the same which in this case 3
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
I GET IT :D
 one year ago

rizwan_uet Group TitleBest ResponseYou've already chosen the best response.2
dw:1359366719099:dw
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
i didnt see you could factorise 3^x out of that equation!! Thanks so much to both of you :)
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.1
You can do the 3^x X 3^x = 3^2x
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
you cant?
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.1
No, because its actually 3^x + ( 5 X 3^x )
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.1
You have to either solve inside the bracket first or factorize
 one year ago

Kuoministers Group TitleBest ResponseYou've already chosen the best response.0
oh thanks @artix_17 for pointing that out!! I wouldn't have noticed :P
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.1
No problem :)
 one year ago
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