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pathosdebater
 2 years ago
Please help!
Use the halfangle identities to express sin 3C in terms of function of 6C.
pathosdebater
 2 years ago
Please help! Use the halfangle identities to express sin 3C in terms of function of 6C.

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hamidic
 2 years ago
Best ResponseYou've already chosen the best response.1sin(6C) = 2 sin(3C) cos(3C) ;then by the sin inverse function 6C=sin1(2s in(3C) cos (3C)

pathosdebater
 2 years ago
Best ResponseYou've already chosen the best response.0(2s in(3c)? Does that mean 2sin^1(3c)?

hamidic
 2 years ago
Best ResponseYou've already chosen the best response.1the answer is 6C = sin1(2 sin(3C) cos(3C) )

pathosdebater
 2 years ago
Best ResponseYou've already chosen the best response.0It's the inverse of sin, so it's sin^1, right?

hamidic
 2 years ago
Best ResponseYou've already chosen the best response.1yes its the inverse of sin
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