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 one year ago
Please help!
Use the halfangle identities to express sin 3C in terms of function of 6C.
 one year ago
Please help! Use the halfangle identities to express sin 3C in terms of function of 6C.

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hamidic
 one year ago
Best ResponseYou've already chosen the best response.1sin(6C) = 2 sin(3C) cos(3C) ;then by the sin inverse function 6C=sin1(2s in(3C) cos (3C)

pathosdebater
 one year ago
Best ResponseYou've already chosen the best response.0(2s in(3c)? Does that mean 2sin^1(3c)?

hamidic
 one year ago
Best ResponseYou've already chosen the best response.1the answer is 6C = sin1(2 sin(3C) cos(3C) )

pathosdebater
 one year ago
Best ResponseYou've already chosen the best response.0It's the inverse of sin, so it's sin^1, right?

hamidic
 one year ago
Best ResponseYou've already chosen the best response.1yes its the inverse of sin
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