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pathosdebater
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Please help!
Use the halfangle identities to express sin 3C in terms of function of 6C.
 one year ago
 one year ago
pathosdebater Group Title
Please help! Use the halfangle identities to express sin 3C in terms of function of 6C.
 one year ago
 one year ago

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hamidic Group TitleBest ResponseYou've already chosen the best response.1
sin(6C) = 2 sin(3C) cos(3C) ;then by the sin inverse function 6C=sin1(2s in(3C) cos (3C)
 one year ago

pathosdebater Group TitleBest ResponseYou've already chosen the best response.0
(2s in(3c)? Does that mean 2sin^1(3c)?
 one year ago

hamidic Group TitleBest ResponseYou've already chosen the best response.1
the answer is 6C = sin1(2 sin(3C) cos(3C) )
 one year ago

pathosdebater Group TitleBest ResponseYou've already chosen the best response.0
It's the inverse of sin, so it's sin^1, right?
 one year ago

hamidic Group TitleBest ResponseYou've already chosen the best response.1
yes its the inverse of sin
 one year ago
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