anonymous
  • anonymous
Please help! Use the half-angle identities to express sin 3C in terms of function of 6C.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
sin(6C) = 2 sin(3C) cos(3C) ;then by the sin inverse function 6C=sin-1(2s in(3C) cos (3C)
anonymous
  • anonymous
(2s in(3c)? Does that mean 2sin^-1(3c)?
anonymous
  • anonymous
the answer is 6C = sin-1(2 sin(3C) cos(3C) )

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anonymous
  • anonymous
It's the inverse of sin, so it's sin^-1, right?
anonymous
  • anonymous
yes its the inverse of sin

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