A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Is there any formula for this
1^n +2^n +3^n +...+x^n
anonymous
 3 years ago
Is there any formula for this 1^n +2^n +3^n +...+x^n

This Question is Closed

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.0why don't you try for a derivation ?

amoodarya
 3 years ago
Best ResponseYou've already chosen the best response.0yes but is very complicated ! look these 1+2+3 + ...n=n(n+1)/2 1^2+2^2 +...n^2=n(n+1)(2n+1)/6 1^3+2^3+...+n^3=(n(n+1)/2)^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Cant it be expressed interms of x and n

amoodarya
 3 years ago
Best ResponseYou've already chosen the best response.0its not easy to write when n is >4 but look 1+2+3+ ...+x=x(x+1)/2 is that "what you mean "?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.3Well these is no standard formula, you can only derive that formula for summation(i^n) if you know the value of summation(i^ (n1)) which will require knowledge of summation(i^(n2)) and so on.. :

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0This reminds me of a pseries... \[\large \sum_{k=1}^{x}\frac{1}{k^{p}}\] And then just set p = n... But we don't have such an expression for the x'th partial sum as far as I know, for any pseries

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0Well, except for the ones @amoodarya mentioned, anyway.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.