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CAn U find the derivative for this equation PLZ TT^TT

Mathematics
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\[\sin (xy)+^{2} = x -y\]
oh no -.-
\[\sin (xy) + x^{2} = x - y\]

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Other answers:

oh boy..... I'm sorry, but I didnt do very well in Geometry... :-/
:] weeee xD everybody is smart except me
thats calculas -.-
O_O
who can solve this TT___TT
i tell you what i got
and i know its wrong
\[y \prime(xy+y) = -\cos (xy)y-2x\]
it wrong i know -..-
please do not underestimate yourself!! we are all people just like you :)
please !!! i thought u were going to type the answer
=_=
i am doing on paper 1 sec :)
:B
do you want to solve for y' ?
yup
ok lets do it together take first term
first you will get \[\cos xy \] apply chain rule and use product rule for xy
that will be?
\[y \prime =\frac{ -\cos (xy)y -2x }{ (xy+y) }\] ?
there is a mistake ..lets do afresh that will help you more :)
so answer my qn above did you differentiate first term ?
tell me what you get?
cos (xy) (y+x y prime ) ??
yep :) \[\cos (xy)(xy'+y) \] who told you are dump ?
now next term :)
\[\dfrac{dy}{dx} x^2=?\]
cos(xy)(xy′+y)+2x = -y′
good but there is a small mistake :) check again ?
i see no mistake sir -.-
oh right ;B
cos(xy)(xy′+y)+2x = 1 -y′
:) now i feel like i am dump :P
xD .. its okie i think i got it now
thanks
:) good ..a medal for your intelligence XD
:P
thanks and bye .. ;) talk to u later igtg complete studying :B
ok best of luck :)

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