Alice_Dump
CAn U find the derivative for this equation PLZ TT^TT



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Alice_Dump
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\[\sin (xy)+^{2} = x y\]

Alice_Dump
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oh no .

Alice_Dump
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\[\sin (xy) + x^{2} = x  y\]

Ookami
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oh boy..... I'm sorry, but I didnt do very well in Geometry... :/

Alice_Dump
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:] weeee xD
everybody is smart except me

Alice_Dump
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thats calculas .

Alice_Dump
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O_O

Alice_Dump
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who can solve this TT___TT

Alice_Dump
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i tell you what i got

Alice_Dump
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and i know its wrong

Alice_Dump
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\[y \prime(xy+y) = \cos (xy)y2x\]

Alice_Dump
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it wrong i know ..

AravindG
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please do not underestimate yourself!! we are all people just like you :)

Alice_Dump
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please !!!
i thought u were going to type the answer

Alice_Dump
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=_=

AravindG
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i am doing on paper 1 sec :)

Alice_Dump
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:B

AravindG
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do you want to solve for y' ?

Alice_Dump
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yup

AravindG
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ok lets do it together take first term

AravindG
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first you will get \[\cos xy \]
apply chain rule and use product rule for xy

AravindG
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that will be?

Alice_Dump
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\[y \prime =\frac{ \cos (xy)y 2x }{ (xy+y) }\] ?

AravindG
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there is a mistake ..lets do afresh that will help you more :)

AravindG
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so answer my qn above did you differentiate first term ?

AravindG
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tell me what you get?

Alice_Dump
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cos (xy) (y+x y prime ) ??

AravindG
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yep :)
\[\cos (xy)(xy'+y) \]
who told you are dump ?

AravindG
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now next term :)

AravindG
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\[\dfrac{dy}{dx} x^2=?\]

Alice_Dump
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cos(xy)(xy′+y)+2x = y′

AravindG
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good but there is a small mistake :) check again ?

Alice_Dump
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i see no mistake sir .

Alice_Dump
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oh right ;B

Alice_Dump
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cos(xy)(xy′+y)+2x = 1 y′

AravindG
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:) now i feel like i am dump :P

Alice_Dump
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xD ..
its okie i think i got it now

Alice_Dump
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thanks

AravindG
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:) good ..a medal for your intelligence XD

Alice_Dump
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:P

Alice_Dump
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thanks and bye ..
;) talk to u later igtg complete studying :B

AravindG
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ok best of luck :)