Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

frx

  • 2 years ago

A particle moves around a circle x^2+y^2=25 at constant speed, making one revolution in 2 seconds. Find its acceleration when it is at (3,4) I have absolutly no idea how to transform x^2+y^2=25 into a vectorequation on the from \[r= x(t) i + y(t)j+z(t)k\], it would be very much appreciated with some help.

  • This Question is Closed
  1. dumbcow
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    first thought is if it has constant velocity .... then acceleration must be 0

  2. frx
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Indeed, that was my first thought to but the key says \[a=-3\pi ^{2}i-4\pi ^{2}j\]

  3. dumbcow
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh ok, to define circle in vector form use sin and cos x(t) = Acos(Bt) y(t) = Asin(Bt) A is radius , B is speed (radians per sec) A = 5 period = 2 --> B = 2pi/2 = pi x(t) = 5cos(pi*t) y(t) = 5sin(pi*t) now find 2nd derivatives to get accelerations

  4. frx
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh I see, thanks!

  5. dumbcow
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yw

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.