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AmberBamber
Group Title
(Precal: law of cosines)
Find the area of the triangle.
A=47 degrees
b=32ft
c=19 ft
@amistre64
 one year ago
 one year ago
AmberBamber Group Title
(Precal: law of cosines) Find the area of the triangle. A=47 degrees b=32ft c=19 ft @amistre64
 one year ago
 one year ago

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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
law of cosine is a general version of the pythag thrm
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
in this case: a^2 = b^2 + c^2  2bc cosA
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
when the angle given is 90 degrees this simplifies to: a^2 = b^2 + c^2 such that a is the hypotenuse
 one year ago

AmberBamber Group TitleBest ResponseYou've already chosen the best response.0
Oh, so I need to find a before I can do s=a+b+c/2 and plug in for are.
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
dw:1359387445633:dw
 one year ago

AmberBamber Group TitleBest ResponseYou've already chosen the best response.0
Then plug in s and the values of a, b, and c in the area formula. A=sqrts(sa)(sb)(sc)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
if you want to do herons formula then yes, you would need to know all the side lengths
 one year ago

AmberBamber Group TitleBest ResponseYou've already chosen the best response.0
Okay, well that's the only way I learned so I'm going to do it that way. But thank you! I needed a refresher :)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
good luck :)
 one year ago

AmberBamber Group TitleBest ResponseYou've already chosen the best response.0
Thanks. :)
 one year ago
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