anonymous
  • anonymous
(Pre-cal: law of cosines) Find the area of the triangle. A=47 degrees b=32ft c=19 ft @amistre64
Mathematics
schrodinger
  • schrodinger
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amistre64
  • amistre64
law of cosine is a general version of the pythag thrm
amistre64
  • amistre64
in this case: a^2 = b^2 + c^2 - 2bc cosA
amistre64
  • amistre64
when the angle given is 90 degrees this simplifies to: a^2 = b^2 + c^2 such that a is the hypotenuse

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anonymous
  • anonymous
Oh, so I need to find a before I can do s=a+b+c/2 and plug in for are.
anonymous
  • anonymous
area*
amistre64
  • amistre64
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anonymous
  • anonymous
Then plug in s and the values of a, b, and c in the area formula. A=sqrts(s-a)(s-b)(s-c)
amistre64
  • amistre64
if you want to do herons formula then yes, you would need to know all the side lengths
anonymous
  • anonymous
Okay, well that's the only way I learned so I'm going to do it that way. But thank you! I needed a refresher :)
amistre64
  • amistre64
good luck :)
anonymous
  • anonymous
Thanks. :)

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