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sue101
 2 years ago
Sketch the asymptotes, and graph the function. y = 5/(x3) + 2
sue101
 2 years ago
Sketch the asymptotes, and graph the function. y = 5/(x3) + 2

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Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.3Well, I see that x=3 causes the denominator to be 0 so there is a vertical asymptote at x=3 and since the degree of the numerator is less than the degree of the denominator, there is a horizontal asymptote at y = 2

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.3So the graph will have two branches like this: dw:1359402444994:dw
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