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sue101

  • one year ago

Sketch the asymptotes, and graph the function. y = 5/(x-3) + 2

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  1. sue101
    • one year ago
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  2. sue101
    • one year ago
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    @satellite73 @Mertsj

  3. Mertsj
    • one year ago
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    Well, I see that x=3 causes the denominator to be 0 so there is a vertical asymptote at x=3 and since the degree of the numerator is less than the degree of the denominator, there is a horizontal asymptote at y = 2

  4. Mertsj
    • one year ago
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    So the graph will have two branches like this: |dw:1359402444994:dw|

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