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sue101
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Sketch the asymptotes, and graph the function. y = 5/(x3) + 2
 one year ago
 one year ago
sue101 Group Title
Sketch the asymptotes, and graph the function. y = 5/(x3) + 2
 one year ago
 one year ago

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sue101 Group TitleBest ResponseYou've already chosen the best response.1
@satellite73 @Mertsj
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
Well, I see that x=3 causes the denominator to be 0 so there is a vertical asymptote at x=3 and since the degree of the numerator is less than the degree of the denominator, there is a horizontal asymptote at y = 2
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.1
So the graph will have two branches like this: dw:1359402444994:dw
 one year ago
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