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sue101
Sketch the asymptotes, and graph the function. y = 5/(x-3) + 2
Well, I see that x=3 causes the denominator to be 0 so there is a vertical asymptote at x=3 and since the degree of the numerator is less than the degree of the denominator, there is a horizontal asymptote at y = 2
So the graph will have two branches like this: |dw:1359402444994:dw|