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dmartinez130 Group Title

Height of a Projectile: The height of an object thrown upward from the roof of a building 408 ft tall, with an initial velocity of 96 ft/sec, is given by the equation h=-16t^2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?

  • one year ago
  • one year ago

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  1. him1618 Group Title
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    when it falls on the ground what is the value of h??

    • one year ago
  2. dmartinez130 Group Title
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    0

    • one year ago
  3. him1618 Group Title
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    so set that = 0 in the equation

    • one year ago
  4. dmartinez130 Group Title
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    So it's -16t^2+96t+408=0?

    • one year ago
  5. him1618 Group Title
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    yes...now solve for t

    • one year ago
  6. dmartinez130 Group Title
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    Can you show me the steps please?

    • one year ago
  7. him1618 Group Title
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    -16t^2 + 96t + 408=0 solve the quadratic equation

    • one year ago
  8. dmartinez130 Group Title
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    Can you show me the steps please?

    • one year ago
  9. Mertsj Group Title
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    \[x=\frac{-96\pm \sqrt{96^2-4(-16)(408)}}{2(-16)}\]

    • one year ago
  10. Mertsj Group Title
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    Simplify that.

    • one year ago
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