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dmartinez130
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Height of a Projectile: The height of an object thrown upward from the roof of a building 408 ft tall, with an initial velocity of 96 ft/sec, is given by the equation h=16t^2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?
 one year ago
 one year ago
dmartinez130 Group Title
Height of a Projectile: The height of an object thrown upward from the roof of a building 408 ft tall, with an initial velocity of 96 ft/sec, is given by the equation h=16t^2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?
 one year ago
 one year ago

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him1618 Group TitleBest ResponseYou've already chosen the best response.0
when it falls on the ground what is the value of h??
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
so set that = 0 in the equation
 one year ago

dmartinez130 Group TitleBest ResponseYou've already chosen the best response.0
So it's 16t^2+96t+408=0?
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
yes...now solve for t
 one year ago

dmartinez130 Group TitleBest ResponseYou've already chosen the best response.0
Can you show me the steps please?
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
16t^2 + 96t + 408=0 solve the quadratic equation
 one year ago

dmartinez130 Group TitleBest ResponseYou've already chosen the best response.0
Can you show me the steps please?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
\[x=\frac{96\pm \sqrt{96^24(16)(408)}}{2(16)}\]
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Simplify that.
 one year ago
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