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dmartinez130

  • 3 years ago

Height of a Projectile: The height of an object thrown upward from the roof of a building 408 ft tall, with an initial velocity of 96 ft/sec, is given by the equation h=-16t^2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?

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  1. him1618
    • 3 years ago
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    when it falls on the ground what is the value of h??

  2. dmartinez130
    • 3 years ago
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    0

  3. him1618
    • 3 years ago
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    so set that = 0 in the equation

  4. dmartinez130
    • 3 years ago
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    So it's -16t^2+96t+408=0?

  5. him1618
    • 3 years ago
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    yes...now solve for t

  6. dmartinez130
    • 3 years ago
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    Can you show me the steps please?

  7. him1618
    • 3 years ago
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    -16t^2 + 96t + 408=0 solve the quadratic equation

  8. dmartinez130
    • 3 years ago
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    Can you show me the steps please?

  9. Mertsj
    • 3 years ago
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    \[x=\frac{-96\pm \sqrt{96^2-4(-16)(408)}}{2(-16)}\]

  10. Mertsj
    • 3 years ago
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    Simplify that.

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