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 2 years ago
Height of a Projectile: The height of an object thrown upward from the roof of a building 408 ft tall, with an initial velocity of 96 ft/sec, is given by the equation h=16t^2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?
 2 years ago
Height of a Projectile: The height of an object thrown upward from the roof of a building 408 ft tall, with an initial velocity of 96 ft/sec, is given by the equation h=16t^2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?

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him1618
 2 years ago
Best ResponseYou've already chosen the best response.0when it falls on the ground what is the value of h??

him1618
 2 years ago
Best ResponseYou've already chosen the best response.0so set that = 0 in the equation

dmartinez130
 2 years ago
Best ResponseYou've already chosen the best response.0So it's 16t^2+96t+408=0?

dmartinez130
 2 years ago
Best ResponseYou've already chosen the best response.0Can you show me the steps please?

him1618
 2 years ago
Best ResponseYou've already chosen the best response.016t^2 + 96t + 408=0 solve the quadratic equation

dmartinez130
 2 years ago
Best ResponseYou've already chosen the best response.0Can you show me the steps please?

Mertsj
 2 years ago
Best ResponseYou've already chosen the best response.0\[x=\frac{96\pm \sqrt{96^24(16)(408)}}{2(16)}\]
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