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First write the equation of the line in point slope form and then rearrange it.

ok one sec

Point slope form is:
\[y-y _{1}=m(x-x _{1})\]

y-(-3)=1/2x-(-1

i have a few others i need help with

\[y+2=\frac{1}{2}(x+2)\]

how did you get 2, the y value is -3

can you just do all the steps up to the last one and i can find the answer then

typo

ok thats what i thought

\[y+3=\frac{1}{2}(x+2)\]
\[y+3=\frac{1}{2}x +1\]
\[\frac{1}{2}x-y=2\]

Or sometimes they want it without fractions in which case it would be:
\[x-2y=4\]

so the answer is x-2y=4

Did you plug in 2 for x and -3 for y and see which one is true?

i don't know what i am looking for though

-3>-2-2, -3>-4
Well shazam!! the very first one is true.

ha ha i was right that is what i thought it was 2 more

Do you know that parallel lines have the same slope?

So this is just like the first one with slope = -4

so it would look like y-(-2)=-4(x-3)

\[y+2=-4(x-3)\]

yep. Now rearrange it.

-5x+y=14 is that the answer

\[y+2=-4x+12\]
\[4x+y=10\]

one more

acctually 2 more

What is the slope of y = x+1?

\[y+1=2x-3\]

\[y=2x-4\]

is that the answer

You didn't answer my question. what is the slope of y=x+1?

Then what is the slope of the perpendicular?

Hint. It is the negative reciprocal of 1

-1

ok. Now use point slope form and plug in the given point and the slope -1

alright one sec

y+1=-2x+3

\[y+1=-1(x-3)\]
y+1=-x+3
\[y=-x+2\]

y=x+2 is the answer

Did you notice the negative sign in front of the x?

What is the vertex of the graph of y = |x - 2|- 5? last one

yes typo

Remember...the slope of the perpendicular is -1

(2,-5)

one more

never mind thank you so much