anonymous
  • anonymous
What is the equation in standard form of the line which passes through (-2, -3) and has a slope of 1/2? Give a medal to first that answers
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Mertsj
  • Mertsj
First write the equation of the line in point slope form and then rearrange it.
anonymous
  • anonymous
ok one sec

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More answers

Mertsj
  • Mertsj
Point slope form is: \[y-y _{1}=m(x-x _{1})\]
anonymous
  • anonymous
y-(-3)=1/2x-(-1
anonymous
  • anonymous
i have a few others i need help with
anonymous
  • anonymous
i did that what is next i put it in to standard form but it never matches up with the answers they give you
Mertsj
  • Mertsj
\[y+2=\frac{1}{2}(x+2)\]
anonymous
  • anonymous
how did you get 2, the y value is -3
anonymous
  • anonymous
can you just do all the steps up to the last one and i can find the answer then
Mertsj
  • Mertsj
typo
anonymous
  • anonymous
ok thats what i thought
Mertsj
  • Mertsj
\[y+3=\frac{1}{2}(x+2)\] \[y+3=\frac{1}{2}x +1\] \[\frac{1}{2}x-y=2\]
Mertsj
  • Mertsj
Or sometimes they want it without fractions in which case it would be: \[x-2y=4\]
anonymous
  • anonymous
so the answer is x-2y=4
anonymous
  • anonymous
To which graph does the point (2, -3) belong? Choose one answer. a. y > -x - 2 b. y > -x - 1 c. y > -2x + 3 d. y > -3x + 5 here is another i need help with
Mertsj
  • Mertsj
Did you plug in 2 for x and -3 for y and see which one is true?
anonymous
  • anonymous
i don't know what i am looking for though
Mertsj
  • Mertsj
-3>-2-2, -3>-4 Well shazam!! the very first one is true.
anonymous
  • anonymous
ha ha i was right that is what i thought it was 2 more
anonymous
  • anonymous
What is the equation of the line in standard form that passes through the point (3, -2) and is parallel to the line y = -4x + 1?
Mertsj
  • Mertsj
Do you know that parallel lines have the same slope?
Mertsj
  • Mertsj
So this is just like the first one with slope = -4
anonymous
  • anonymous
so it would look like y-(-2)=-4(x-3)
Mertsj
  • Mertsj
\[y+2=-4(x-3)\]
Mertsj
  • Mertsj
yep. Now rearrange it.
anonymous
  • anonymous
-5x+y=14 is that the answer
Mertsj
  • Mertsj
\[y+2=-4x+12\] \[4x+y=10\]
anonymous
  • anonymous
one more
anonymous
  • anonymous
acctually 2 more
anonymous
  • anonymous
What is the equation of the line in slope-intercept form that passes through the point (3, -1) and is perpendicular to the line y = x + 1?
Mertsj
  • Mertsj
What is the slope of y = x+1?
anonymous
  • anonymous
1
anonymous
  • anonymous
\[y+1=2x-3\]
anonymous
  • anonymous
\[y=2x-4\]
anonymous
  • anonymous
is that the answer
Mertsj
  • Mertsj
You didn't answer my question. what is the slope of y=x+1?
anonymous
  • anonymous
1
Mertsj
  • Mertsj
Then what is the slope of the perpendicular?
Mertsj
  • Mertsj
Hint. It is the negative reciprocal of 1
anonymous
  • anonymous
-1
Mertsj
  • Mertsj
ok. Now use point slope form and plug in the given point and the slope -1
anonymous
  • anonymous
alright one sec
anonymous
  • anonymous
y+1=-2x+3
Mertsj
  • Mertsj
\[y+1=-1(x-3)\] y+1=-x+3 \[y=-x+2\]
anonymous
  • anonymous
y=x+2 is the answer
Mertsj
  • Mertsj
Did you notice the negative sign in front of the x?
anonymous
  • anonymous
What is the vertex of the graph of y = |x - 2|- 5? last one
anonymous
  • anonymous
yes typo
Mertsj
  • Mertsj
Remember...the slope of the perpendicular is -1
Mertsj
  • Mertsj
(2,-5)
anonymous
  • anonymous
one more
anonymous
  • anonymous
never mind thank you so much

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