roberman228
What is the equation in standard form of the line which passes through (-2, -3) and has a slope of 1/2? Give a medal to first that answers
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roberman228
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@Mertsj
Mertsj
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First write the equation of the line in point slope form and then rearrange it.
roberman228
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ok one sec
Mertsj
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Point slope form is:
\[y-y _{1}=m(x-x _{1})\]
roberman228
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y-(-3)=1/2x-(-1
roberman228
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i have a few others i need help with
roberman228
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i did that what is next i put it in to standard form but it never matches up with the answers they give you
Mertsj
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\[y+2=\frac{1}{2}(x+2)\]
roberman228
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how did you get 2, the y value is -3
roberman228
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can you just do all the steps up to the last one and i can find the answer then
Mertsj
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typo
roberman228
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ok thats what i thought
Mertsj
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\[y+3=\frac{1}{2}(x+2)\]
\[y+3=\frac{1}{2}x +1\]
\[\frac{1}{2}x-y=2\]
Mertsj
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Or sometimes they want it without fractions in which case it would be:
\[x-2y=4\]
roberman228
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so the answer is x-2y=4
roberman228
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To which graph does the point (2, -3) belong?
Choose one answer.
a. y > -x - 2
b. y > -x - 1
c. y > -2x + 3
d. y > -3x + 5
here is another i need help with
Mertsj
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Did you plug in 2 for x and -3 for y and see which one is true?
roberman228
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i don't know what i am looking for though
Mertsj
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-3>-2-2, -3>-4
Well shazam!! the very first one is true.
roberman228
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ha ha i was right that is what i thought it was 2 more
roberman228
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What is the equation of the line in standard form that passes through the point (3, -2) and is parallel to the line y = -4x + 1?
Mertsj
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Do you know that parallel lines have the same slope?
Mertsj
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So this is just like the first one with slope = -4
roberman228
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so it would look like y-(-2)=-4(x-3)
Mertsj
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\[y+2=-4(x-3)\]
Mertsj
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yep. Now rearrange it.
roberman228
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-5x+y=14 is that the answer
Mertsj
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\[y+2=-4x+12\]
\[4x+y=10\]
roberman228
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one more
roberman228
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acctually 2 more
roberman228
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What is the equation of the line in slope-intercept form that passes through the point (3, -1) and is perpendicular to the line y = x + 1?
Mertsj
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What is the slope of y = x+1?
roberman228
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1
roberman228
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\[y+1=2x-3\]
roberman228
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\[y=2x-4\]
roberman228
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is that the answer
Mertsj
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You didn't answer my question. what is the slope of y=x+1?
roberman228
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1
Mertsj
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Then what is the slope of the perpendicular?
Mertsj
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Hint. It is the negative reciprocal of 1
roberman228
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-1
Mertsj
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ok. Now use point slope form and plug in the given point and the slope -1
roberman228
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alright one sec
roberman228
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y+1=-2x+3
Mertsj
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\[y+1=-1(x-3)\]
y+1=-x+3
\[y=-x+2\]
roberman228
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y=x+2 is the answer
Mertsj
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Did you notice the negative sign in front of the x?
roberman228
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What is the vertex of the graph of y = |x - 2|- 5? last one
roberman228
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yes typo
Mertsj
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Remember...the slope of the perpendicular is -1
Mertsj
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(2,-5)
roberman228
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one more
roberman228
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never mind thank you so much