I have no clue how to do this with fractions, someone help and explain in words&numbers please!
As stated:
4(3/4x-7)=4(1/2x+3) Thanks!

- anonymous

- chestercat

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- anonymous

please use the draw tool and write this out

- anonymous

|dw:1359404852432:dw|

- Mertsj

|dw:1359404940241:dw|

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## More answers

- anonymous

sometimes it helps to make the other number a fraction to like this

- anonymous

|dw:1359405028812:dw|

- anonymous

you could even put a 1 under the seven|dw:1359405124046:dw|

- anonymous

Yeah, but how can you multiply the fractions? I tried to remember but I forgot. @moser90

- anonymous

|dw:1359405345652:dw|
do you see what I did

- mathstudent55

|dw:1359405321919:dw|

- anonymous

Oh! yeah, I get it! I get how you multiply the fractions, but then does that mean x will be a fraction?
@mathstudent55

- mathstudent55

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- anonymous

yeah sorry I forgot the x so it would be 3x

- mathstudent55

The 4 outside each parentheses ends up canceling out with the 4 on the left and with the 1/2 on the right leaving a 2, that's why there are no fractions after the 4 is multiplied out. Remember that a number outside parentheses has to be distributed.

- mathstudent55

When you divide the numerator and denominator by the same number, you cross out. It's a way of simplifying the fraction. I can do it without crossing out. I'll show you.

- mathstudent55

|dw:1359405668580:dw|
Now you can reduce the fraction 12/4 and the fraction 4/2 before going on.

- anonymous

|dw:1359405770394:dw|
And I did this, is this correct?

- mathstudent55

12/4 = 3/1 = 3
4/2 = 2/1 = 1
So:
|dw:1359405772980:dw|

- mathstudent55

You are allowed to add 3x to both sides, but in this case it won't help. Also, on the left side, 3x was positive, so you need to subtract 3x, not add 3x. But in the end, it's better to just subtract 2x from both sides, since you have 2x on the right side. By subtracting 2x, you move the x's to the left side.
|dw:1359405951327:dw|

- mathstudent55

And finally:
|dw:1359406000506:dw|

- anonymous

Oh my gosh, thank you!!

- mathstudent55

You're welcome.

- anonymous

I never expected x to be so big. So when I plug the x to make it a 40 and do the "check" side of the problem, I multiply the same way with the fractions as before or do it differently? Like...

- anonymous

|dw:1359406535113:dw|

- mathstudent55

|dw:1359406827973:dw|

- mathstudent55

|dw:1359406928264:dw|

- anonymous

how you make the 40 a ten and 40 a 20?

- mathstudent55

I simplify before multiplying.
Look at the left side. There was a fraction of 3/4 multiplied by the number 40. You can write the number 40 as a fraction, 40/1, and multiply the fractions out:
3/4 * 40/1 = 120/40
Then you need to divide the numerator and denominator by the greatest common factor to reduce the fraction. In this case, the GCF is 40, so
120/40 = 30/1 = 30
What I did wass I reduced before multiplying. Since 40 is divisible by 4, and 4 is in the numerator and 4 is in the denominator, I divided 40 by 4, which is 10. Then when I multiplied 10 times 3 I got 30, which is the same 30 we got by multiplying everything out and reducing.

- anonymous

Ok, that makes sense.

- mathstudent55

On the right side, we had 1/2 times 40. 40 divided by 2 is 20, so you can divide the 40 by the 2 before multiplying by 1, and you get 20. Then you need to multiply by 1, but since multiplying by 1 does not change the number, 20 * 1 = 20.

- anonymous

Thank you for explaining that to me, before I thought I was looking at some kind of messed up nonsense.

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