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JuanitaM
 one year ago
Best ResponseYou've already chosen the best response.0this is the absolute value symbol. What does the directions ask of you?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0it means that the y value of the ordered pair is x^2x and that the answer will be 0 or positive.

tomiko
 one year ago
Best ResponseYou've already chosen the best response.0well it's asking me to find the derivative of that function above. so i'm think there are more than 1 derivatives to find. for instance derivative of f(x) when x >= 0 an derivative when x <0 but i'm not so sure

phi
 one year ago
Best ResponseYou've already chosen the best response.0you could write it as for x≥ 1 f(x)= x^2x for 0≤x ≤1 f(x)= xx^2 for x ≤ 0 f(x)= x^2+x if I did that correctly...

phi
 one year ago
Best ResponseYou've already chosen the best response.0for x <0 x^2x is much better

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.0Remember, the definition of x is: x = x, if x >= 0 x = x, if x < 0. So: f(x) = x^2x means: f(x)= x²  x, if x²  x >= 0 f(x)= x² + x, if x²  x <0 So, to know which of the two formulas applies for certain values of x, you will have to solve x²  x = 0. It has two (simple to find) solutions. Put them on a number line and then make a sign scheme of x²  x. Then you know which of the two formulas applies where...

tomiko
 one year ago
Best ResponseYou've already chosen the best response.0well i have this: http://www.sosmath.com/calculus/diff/der13/img5.gif which i don't understand at all! how the get the if's and how they change the signs.

phi
 one year ago
Best ResponseYou've already chosen the best response.0if x > 1 then x^2 is bigger than x and x^2x is positive  positive # is just the # if x between 0 and 1 x^2 is less than x and x^2 x is negative the absolute value operation changes this to positive: you could say it multiplies by 1: (x^2x)

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.0The sign scheme is (see image). So for 0 < x < 1 you have: f(x) = (x²  x) = x² + x (because x²x is negative there) for x <=0 and for x >=1 you have: f(x) = x²  x (because x²  x is positive there, so you just remove the .. )
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