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ksaimouli
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\[\int\limits_{0}^{3}\sqrt{1+(x \sqrt{x^2+2)}^2} \]

ksaimouli
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can i cancle out the square root by the ^2 of (x^2+2)

ksaimouli
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dw:1359411301194:dw

ksaimouli
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then integrate this am i right

hartnn
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not sure where the ^2 is ...
is it square of [x sqrt (...)]

ksaimouli
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dw:1359411399610:dw

hartnn
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dw:1359411380166:dw
so, yes, you can cancel out...

ksaimouli
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not the inside can i do outside one

hartnn
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dw:1359411478889:dw

hartnn
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\(\sqrt{1+ (x^2)^2+2x^2} = \sqrt{(x^2+1)^2}=x^2+1\)

hartnn
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what ?

ksaimouli
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never mind

hartnn
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you cannot cancel the outside root for ^2 of [x\sqrt...]
so, did you get all steps? any doubt ?

ksaimouli
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yes i got thx

ksaimouli
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congrats u became Ambassador :)

hartnn
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thanks :)