## MariaB2014 Group Title Simplify each expression: click to see please. one year ago one year ago

1. MariaB2014 Group Title

show that $\sqrt[m]{\sqrt[n]{a}}=\sqrt[mn]{a}$

2. tomo Group Title

[(a)^(1/n)]^(1/m) // ok, so just multiply the exponents a^((1/n)*(1/m)) // multiply a^(1/(mn)) // revert back so sqrt form. $\sqrt[mn]{a}$

3. MariaB2014 Group Title

i understood what you're saying but it'd be way better if you can please , put it in regular format, because its confusing .

4. tomo Group Title

do you mean using the equation editor. or are you talking about changing into exponent form. you have to use the exponent form for this problem. (as far as I can tell)

5. MariaB2014 Group Title

yes, the equation editor.

6. klimenkov Group Title

$$\sqrt[m]{\sqrt[n]{a}}=(a^{\frac1 n})^{\frac1m}=a^{\frac1 {mn}}=\sqrt[mn]a$$

7. MariaB2014 Group Title

THANK YOU ! :DD , i understood this.