anonymous
  • anonymous
Simplify each expression: click to see please.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
show that \[\sqrt[m]{\sqrt[n]{a}}=\sqrt[mn]{a}\]
anonymous
  • anonymous
[(a)^(1/n)]^(1/m) // ok, so just multiply the exponents a^((1/n)*(1/m)) // multiply a^(1/(mn)) // revert back so sqrt form. \[\sqrt[mn]{a}\]
anonymous
  • anonymous
i understood what you're saying but it'd be way better if you can please , put it in regular format, because its confusing .

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anonymous
  • anonymous
do you mean using the equation editor. or are you talking about changing into exponent form. you have to use the exponent form for this problem. (as far as I can tell)
anonymous
  • anonymous
yes, the equation editor.
klimenkov
  • klimenkov
\(\sqrt[m]{\sqrt[n]{a}}=(a^{\frac1 n})^{\frac1m}=a^{\frac1 {mn}}=\sqrt[mn]a\)
anonymous
  • anonymous
THANK YOU ! :DD , i understood this.

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