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Smokahontas

  • 3 years ago

Trapezoid problem? (Geometry)

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  1. Smokahontas
    • 3 years ago
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    I set up the equation as 3x+5=1/2[(7x+4)+4] but I got the wrong answer. I dont understand how to do it, please help?

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  2. sirm3d
    • 3 years ago
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    what value of x did you get?

  3. Smokahontas
    • 3 years ago
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    I got 10, but the answer is 11. I dont know how to get 11 though..

  4. sirm3d
    • 3 years ago
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    ah, \(\overline{EF}\) is asked. what did you get for x?

  5. Smokahontas
    • 3 years ago
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    I told you haha, I got 10...

  6. sirm3d
    • 3 years ago
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    something went wrong in your algebra. let's compare results. \[3x+5=(1/2)[(7x+4)+4]\\2(3x+5)=(7x+4)+4\\6x+10=7x+8\]

  7. Smokahontas
    • 3 years ago
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    Where did you get the 2 from? And where did the 1/2 go?

  8. sirm3d
    • 3 years ago
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    i multiplied the first equation by 2 to clear denominator

  9. Smokahontas
    • 3 years ago
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    That would've been better...but if you solve it like that wouldnt x=6?

  10. sirm3d
    • 3 years ago
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    6x+10-6x=7x+8-6x 10 = x + 8 10-8=x-8 2=x

  11. sirm3d
    • 3 years ago
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    \[\overline{EF}=3x+5=3(2)+5=11\]

  12. sirm3d
    • 3 years ago
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    uhm, the third line should read 10-8=x+8-8

  13. Smokahontas
    • 3 years ago
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    Oh I see...but I thought Line EF was half of line BC...?

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