## dainel40 2 years ago The magnitude of F is 384 newtons and it points at 344o measured counterclockwise from the positive x-axis. What is the x component (in newtons) of F?

1. Shane_B

Draw a picture and the answer should be fairly simple:|dw:1359421352236:dw|$|A|=16^{\circ}$$Ax=|A|cos(\theta)$$Ay=|A|sin(\theta)$

2. dainel40

but i don't kno what to do.. Do i subtract 360-344?

3. Shane_B

Yes, to find the angle above (as I did) you do 360-344. That gives you theta

4. Shane_B

So to find the amount of force in just the x direction you would have:$F_x=(384N)cos(16)=369.12N$

5. dainel40

oh

6. dainel40

thanks! so much.. Could i ask u another question if u dont mind?

7. Shane_B

ok

8. dainel40

Question 2 of 6 -F points in the opposite direction as F and has the same magnitude as F True/False Question 3 of 6 F1 = (8.4,3.4) and F2 = (-7.1,-5.8) where all components are in newtons. What is the exact x-component of F1 + F2 (in newtons)?

9. Shane_B

The first one is true. For the second one you have to do vector addition: F1=(8.4,3.4) which states that the x value is 8.4 and the y value is 3.4. F2=(-7.1,-5.8) which states that the x value is -7.1 and the y value is -5.8. The resultant vector (in component notation) will simply be: Fresult=[(8.4+(-7.1)), (3.4+(-5.8))]Just perform the math and you'll know what the answer to the second question is.

10. dainel40

dont i just need the value of x? so it will be 8.4+-7.1 = 1.3

11. Shane_B

If it's not clear, I'm just adding the x's and y's. You should end up with Fresult=(1.3, -2.4)

12. Shane_B

Yes

13. dainel40

ok thanks!. how would u do this question. F = (30.8,44.4), where all components are in newtons. If a vector's direction is measured counterclockwise from the positive x-axis, what angle (in degrees, from 0-360) does the negative vector -F make?

14. dainel40

Can I do opp/adj and then find the inverse tangent?

15. dainel40

to get the angle

16. Shane_B

Yes

17. Cloverpetal

hey, @Shane_B when you're done, wanna help me? :)

18. Shane_B

|dw:1359423352611:dw|

19. Shane_B

A better picture...

20. dainel40

ok thanks!

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