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samw24
A 500 kg crate is lifted to the top of the new event center with an acceleration of 1.69. (a) Find the force exerted by the cable on the crate. (b) If the cable is rated for a maximum force of 13000 N, what is the maximum acceleration possible without braking the cable?
a) Weight mg acts downwards and tension T acts upwards T-mg=ma Calculate for T b) Here we are provided the maximum value of T . corresponding to the maximum value of T we get the maximum acceleration. Put the value of T and get a.