anonymous
  • anonymous
Graph piecewise function: p(x)={1/2x+1 if x cannot equal to 4 {2 if x = 4 State Domain and Range
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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zepdrix
  • zepdrix
|dw:1359425377274:dw|Basically what we want to do is - think of this as two different functions. It's the function \(p(x)=\dfrac{1}{2}x+1\) when `x is not 4`. And it's a different function \(q(x)=2\) when `x is 4`. So let's graph what I called `q` first, since that one is easy. c:
anonymous
  • anonymous
ok :)
anonymous
  • anonymous
so when x is not 4, that mean i can select x to be any number just dont pick 4 right ?

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zepdrix
  • zepdrix
For all values of x, the function produces `2`. Normally that would look like a horizontal line like this,|dw:1359425605017:dw|But this function is only defined at x=4! So what we actually get is this.|dw:1359425634168:dw|
zepdrix
  • zepdrix
Oh sorry I was looking at the `x is 4` one first c: heh
anonymous
  • anonymous
oh
zepdrix
  • zepdrix
I should delete that line on x=4.. I think that's confusing maybe.
anonymous
  • anonymous
plz keep explaining...i got emergency but i brb thanks! :]
zepdrix
  • zepdrix
k
zepdrix
  • zepdrix
When `x is not 4` we have a linear function. It has a slope of 1/2, and a y-intercept of 1.
zepdrix
  • zepdrix
So it will cross the y-axis at y=1
zepdrix
  • zepdrix
|dw:1359425801166:dw|Remember, we can only graph this line where `x is not 4`. So when we get to that spot where x is 4, we draw an open circle to show that the line is not defined there.
zepdrix
  • zepdrix
The black dots on the left don't actually mean anything. I was just plotting a couple points so I could draw a line through them.
anonymous
  • anonymous
@zepdrix what about the green dot ?
anonymous
  • anonymous
so when x cannot equal to 4 then just don't include the 4
anonymous
  • anonymous
oh i see now, the green dot is x=4 and it just a linear line
zepdrix
  • zepdrix
Yah the green dot is where the function is defined when `x=4`. It's like you have a straight line, with a hole in it at one spot. Think of a straight line, and one of the points broke off the line and fell to a spot below somewhere. The function is still defined at x=4, just in a different place, not along the line where you would normally think. Sorry late response :C site being slow tonight.

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