## Subrina Group Title Fine the measures of the numbered angles and then find area ( Rhombus) one year ago one year ago

1. sauravshakya Group Title

figure?

2. Subrina Group Title

sorry that wasnt my question but I can post it

3. Subrina Group Title

my picture

4. sauravshakya Group Title

sorry, figure is quite not clear

5. Subrina Group Title
6. sauravshakya Group Title

|dw:1359428413420:dw|

7. Subrina Group Title

how did you get that

8. sauravshakya Group Title

|dw:1359428663385:dw|

9. sauravshakya Group Title

Now, AREA of rhombus =4*1/2 *4/2 *7/2

10. whpalmer4 Group Title

A different way to the same result: the diagonal of the rhombus bisects the angles, so we have pairs of 30 angles at each narrow end, and the sum of the interior angles must be (4-2)*180 = 360, and we've already accounted for 4*30 = 120 of that, so that leaves (360-120)/2 = 120 for each pair on the blunt angles, or 60 each.

11. Subrina Group Title

dont you do 1/2 d1*d2

12. whpalmer4 Group Title

Yes, the area of a rhombus is given by $$\frac{1}{2}d_1d_2$$ so all you need now is the lengths of the two diagonals. Do you know them?

13. Subrina Group Title

is it 1/2 16*14=112

14. whpalmer4 Group Title

Looks to me like the half diagonals are 7m and 4m, aren't they? So 14 and 8 would be the full diagonals?

15. Subrina Group Title

yes your right so then u would slove it then get 56 as answer

16. whpalmer4 Group Title

Yes, I believe that is correct.

17. Subrina Group Title

ok